Answer:
The number of days is at most 5 days
= d ≤ 5 days
Step-by-step explanation:
A rental car company charges $31 per day to rent a car and $0.13 for every mile driven. Jocelyn wants to rent a car, knowing that:
She plans to drive 500 miles.
• She has at most $220 to spend.
At most means Less than or equal to $220
The inequality for expressing this = ≤
Hence, the inequality which can be used to determine d, the number of days Jocelyn can afford to rent while staying within her budget.
$31 × d + $0.13 × 500 miles ≤ $200
The inequality is given as:
31d + 65 ≤ 220
Solving further
31d ≤ 220 -65
31d ≤ 155
d ≤ 155/31
d ≤ 5
Therefore, the number of days is at most 5 days
Let x = amount invested in 2% CD and y = amount invested in 3% CD
x + y = 60000
0.02x + 0.03y = 1600
SOLVE THE 1st EQUATION FOR x AND SUBSTITUTE RESULT IN 2nd
0.02(60000 - y) + 0.03y = 1600
1200 - 0.02y + 0.03y = 1600
0.03y = 400
y = 13333.34
x = 46666.66
Answer:
the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days
Step-by-step explanation:
Given that :
Mean = 265
standard deviation = 14
The formula for calculating the z score is 
x = μ + σz
At middle of 50% i.e 0.50
The critical value for 
From standard normal table
+ 0.67 or -0.67
So; when z = -0.67
x = μ + σz
x = 265 + 14(-0.67)
x = 265 -9.38
x = 255.62
when z = +0.67
x = μ + σz
x = 265 + 14 (0.67)
x = 265 + 9.38
x = 274.38
the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days
Answer:
-9
Step-by-step explanation:
