Answer:
the dark purple in the bottom, brown reddish one light purple one in the bottom
Step-by-step explanation:
The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
As you can see below, in
red is <span>g(x) = (x + 1)^3 and in
blue is f(x)=x^3. Adding 1 to x
moves the graph to the left by 1. Hope this was the answer you were looking for and I hope you have a great day!
</span>
Answer:
4
Step-by-step explanation:
d - 9 = -5
Add 9 to -5, and you will get 4.
4 - 9 = -5
