Answer:
x = 28
Step-by-step explanation:
If AB and CD are the straight lines, sum all the angles formed at a point lying on this line will be 180°.
m∠COE + m∠EOF + m∠FOB + m∠BOD = 180° [Angles at a point O on line AB]
3x + x + (x + 12) + m∠BOD = 180°
m∠BOD = 180° - (5x + 12)
Similarly, m∠AOD + m∠AOC = 180°
152° + m∠AOC = 180°
m∠AOC = 28°
Since, ∠AOC and ∠BOD are the vertical angles,
m∠AOC = m∠BOD
180° - (5x + 12)° = 28°
5x + 12 = 180 - 28
5x = 140
x = 28
Answer:
EF=20
Step-by-step explanation:
EF is midsegment of the triangle so the equation is
AB/2=EF
7x-2/2=2x+8
7x-2=4x+16
7x-4x=16+2
3x=18
x=18/3
x=6
EF=2×6+8
=12+8
=20
I think that would be one . A=s*s A=1*1
I'm not Totally sure but I'm pretty sure its B<span />
First step is to plot all the given coordinates in the xy plane.
Notice that after plotting the points A, B, C and D, we have got the figure ABCD is a trapezium with bases AD = 4 units, BC = 6 units and height: DE= 5 units.
Formula to find the area of trapezium is:
Area = 
= 
=
= 5 * 5
= 25 square units.
So, third choice is correct.
Hope this helps you!
