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koban [17]
3 years ago
11

The measure of an angle is seventy-one times the measure of its supplementary angle. What is the measure of each angle?

Mathematics
1 answer:
Degger [83]3 years ago
4 0

Answer:

2 degrees and 178 degrees.

Step-by-step explanation:

So, remember if 2 angles are supplementary, they equal 180 degrees. Let's call the smaller angle x, meaning the bigger angle, which is 89 times the size of the smaller angle, would be 89x. Now let's put that into an equation.

180 = x + 89x

We now have to group the x's together:

180 = 90x

Now in order to determine x, we have to divide by 90 on both sides.

X= 2

So we know that the smaller angle is 2, meaning that if the larger angle is 89 times the size, the larger angle would be 178.

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Jeb bought a $5 Footlong TM. Sales tax was 8%. How much was sales tax for the sandwich
Katen [24]

C)5.40

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Step-by-step explanation:

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4 0
2 years ago
Find the integration of (1-cos2x)/(1+cos2x)
slega [8]

Given:

The expression is:

\dfrac{1-\cos 2x}{1+\cos 2x}

To find:

The integration of the given expression.

Solution:

We need to find the integration of \dfrac{1-\cos 2x}{1+\cos 2x}.

Let us consider,

I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx

I=\int \dfrac{2\sin^2x}{2\cos^2x}dx         [\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]

I=\int \dfrac{\sin^2x}{\cos^2x}dx

I=\int \tan^2xdx                      \left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]

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I=\int (\sec^2x-1)dx             [\because 1+\tan^2 \theta =\sec^2 \theta]

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I=\tan x-x+C

Therefore, the integration of \dfrac{1-\cos 2x}{1+\cos 2x} is I=\tan x-x+C.

8 0
3 years ago
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