Answer:
(x^4-8)^45 /180 +c
Step-by-step explanation:
If u=x^4-8, then du=(4x^3-0)dx or du=4x^3 dx by power and constant rule.
If du=4x^3 dx, then du/4=x^3 dx. I just divided both sides by 4.
Now we are ready to make substitutions into our integral.
Int(x^3 (x^4-8)^44 dx)
Int(((x^4-8)^44 x^3 dx)
Int(u^44 du/4)
1/4 Int(u^44 dul
1/4 × (u^45 / 45 )+c
Put back in terms of x:
1/4 × (x^4-8)^45/45 +c
We could multiply those fractions
(x^4-8)^45 /180 +c
Both of those equations are solved for y. So if the first one is equal to y and the second one is equal to y, then the transitive property says that the first one is equal to the second one. We set them equal to each other and solve for x. 4x-5=-3 and 4x = 2. That means that x = 1/2. We were already told that y = -3, so the coordinates for the solution to that system are (1/2, -3), B from above.
Given u/7 - 1 = 7 and plugging in values for u,
For u = 28; 28/7 - 1 = 4 - 1 = 3; No
For u = -49; -49/7 - 1 = -7 - 1 = -8; No
For u = 42; 42/7 - 1 = 6 - 1 = 5; No
For u = 0; 0/7 - 1 = -1; No
Another way to find out which value would be a solution to u/7 - 1 = 7 is to solve for u.
u/7 - 1 = 7
u/7 = 7 + 1
u/7 = 8
u = 8*7
u = 56
The only solution to this equation is when u = 56.
A half of 4 is 2 because 2+2=4
Answer:
the first one is -9/40. the second one is 109/20. the third one is -8/35.
Step-by-step explanation:
here is the work for the first one 3/8-.6 and convert into a simplified fraction and came up with -9/40. here is the work for the second one 4 4/3+0.7 and then convert into a simplified fraction and came up with 109/20. here is the work for the third one 4/7-0.8 and then convert into a simplified fraction and came up with -8/35.
