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3 years ago

Next Question!

Mathematics

2 answers:

rodikova [14]3 years ago

6 0

Answer:

1/6≈0.17≈17%

Step-by-step explanation:

klasskru [66]3 years ago

3 0

1/3 because M and P are 2/6 letters on the wheel and 2/6 is equal to 1/3

You might be interested in

Solve for n or d27/36=n/4

Vlada [557]

27/36 = n/4
27*4 = 36n
108 = 36n
108/36 = 36n/36
n = 3

5 0

3 years ago

Let S be the solid beneath z = 12xy^2 and above z = 0, over the rectangle [0, 1] × [0, 1]. Find the value of m > 1 so that th

jonny [76]

Answer:

The answer is $\sqrt{\frac{6}{5}}$

Step-by-step explanation:

To calculate the volumen of the solid we solve the next double integral:

$\int\limits^1_0\int\limits^1_0 {12xy^{2} } \, dxdy$

Solving:

$\int\limits^1_0 {12x} \, dx \int\limits^1_0 {y^{2} } \, dy$

$[6x^{2} ]{{1} \atop {0}} \right. * [\frac{y^{3}}{3}]{{1} \atop {0}} \right.$

Replacing the limits:

$6*\frac{1}{3} =2$

The plane y=mx divides this volume in two equal parts. So volume of one part is 1.

Since m > 1, hence mx ≤ y ≤ 1, 0 ≤ x ≤ $\frac{1}{m}$

Solving the double integral with these new limits we have:

$\int\limits^\frac{1}{m} _0\int\limits^{1}_{mx} {12xy^{2} } \, dxdy$

This part is a little bit tricky so let's solve the integral first for dy:

$\int\limits^\frac{1}{m}_0 [{12x \frac{y^{3}}{3}}]{{1} \atop {mx}} \right.\, dx =\int\limits^\frac{1}{m}_0 [{4x y^{3 }]{{1} \atop {mx}} \right.\, dx$

Replacing the limits:

$\int\limits^\frac{1}{m}_0 {4x(1-(mx)^{3} )\, dx =\int\limits^\frac{1}{m}_0 {4x-4x(m^{3} x^{3} )\, dx =\int\limits^\frac{1}{m}_0 ({4x-4m^{3} x^{4}) \, dx$

Solving now for dx:

$[{\frac{4x^{2}}{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right. = [{2x^{2} -\frac{4m^{3} x^{5}}{5} ]{{\frac{1}{m} } \atop {0}} \right.$

Replacing the limits:

$\frac{2}{m^{2} }-\frac{4m^{3}\frac{1}{m^{5}}}{5} =\frac{2}{m^{2} }-\frac{4\frac{1}{m^{2}}}{5} \\ \frac{2}{m^{2} }-\frac{4}{5m^{2} }=\frac{10m^{2}-4m^{2} }{5m^{4}} \\ \frac{6m^{2} }{5m^{4}} =\frac{6}{5m^{2}}$

As I mentioned before, this volume is equal to 1, hence:

$\frac{6}{5m^{2}}=1\\m^{2} =\frac{6}{5} \\m=\sqrt{\frac{6}{5} }$

3 0

3 years ago

A building may fail by excessive settlement of the foundation or by collapse of the superstructure. Over the life of the buildin

patriot [66]

Answer:

0.1536

Step-by-step explanation:

The computation of probability that the building failure will occur over its life is shown below:-

P(building failure) is

$P(ES \cup C)\\\\ = P(ES) + P(C) - P(ES\cap C)\\\\ = P(ES) + P(C) - P(ES) P (C | ES)\\\\ = 0.12 + 0.06 - 0.12 \times 0.22$

now we will solve the above equation

= 0.18 - 0.0264

After solving the above equation we will get

= 0.1536

Therefore for computing the probability that the building failure will occur over its life we simply applied the above formula.

3 0

3 years ago

What is the volume of a cone with radius 7 cm and height 11 cm? Round your answer to two decimal places.

a_sh-v [17]

Answer:

D. 564.44 cm^3

Step-by-step explanation:

V = (1/3)(pi)r^2h

V = (1/3)(3.14159)(7 cm)^2(11 cm)

V = 564.44 cm^3

5 0

3 years ago

Find the inverse of: f(x)=3x-8

Crazy boy [7]

The answer is f^-1(x)=8/3+x/3

8 0

3 years ago