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frez [133]
3 years ago
15

Pls answer. i will mark u as branliest

Mathematics
2 answers:
kumpel [21]3 years ago
5 0

Answer:

60

Step-by-step explanation:

All angles = 180

All sides are equal

Therefore, 180/3 = angle degrees = 60

x is an opposite angle of bottom right angle therfore x = 60

nordsb [41]3 years ago
3 0

Answer:

(a) x = 60°

(b) Angle x is alternate to the right base angle of the equilateral triangle.

Step-by-step explanation:

(a) The triangle in the figure above is an equilateral triangle in which all sides and angles are equal. The sum of angles in a triangle is 180°. Each angle in the equilateral triangle is 60° (180°/3 = 60°)

Therefore, angle x is 60°.

(b) Alternate angles are equal. Angle x and the right base angle of the equilateral triangle are alternate angles. Therefore, angle x is 60°.

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Solve for x where xe(0,2pi). state exact answers.
kupik [55]

Answer:

that's the correct answer

6 0
2 years ago
Ben bowled 121 and 184 in his first two games. What must he bowl in his third game to have an average of at least 170​?
vagabundo [1.1K]

Answer:

205

Step-by-step explanation:

Were gonna start by writing an equation (121+184+x)/3=170 because were adding a 3rd value to the average and x is going to be our value that were looking for. If you solve that, you get 205. Hope this helps.

6 0
3 years ago
What are the domain and range of f(x) = 2|x -4|? <br> plz i'm in need
mafiozo [28]

Answer:

Domain: (-∞, ∞)

Range: [0, ∞)

Step-by-step explanation:

The domain represents what x can be. In this scenario, we do not have x as a denominator, and there is nothing limiting x, so its domain is (-∞, ∞)

The range represents what f(x) can be, Because |x-4| is in absolute value, the lowest |x-4| can be is 0, and as a result, the lowest value of 2|x-4| is 2*0=0. The maximum value of f(x) is ∞ as an absolute value does not limit the maximum, making the range [0, ∞)

6 0
3 years ago
Let f(x) = (x − 3)−2. Find all values of c in (1, 7) such that f(7) − f(1) = f '(c)(7 − 1). (Enter your answers as a comma-separ
Sidana [21]

Answer:

This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f '(c) = f(7) − f(1) (7 − 1) , but f is not continuous at x = 3

Step-by-step explanation:

The given function is

f(x)=(x-3)^{-2}

When we differentiate this function with respect to x, we get;

f'(x)=-\frac{2}{(x-3)^3}

We want to find all values of c in (1,7) such that f(7) − f(1) = f '(c)(7 − 1)

This implies that;

0.06-0.25=-\frac{2}{(c-3)^3} (6)

-0.19=-\frac{12}{(c-3)^3}

(c-3)^3=\frac{-12}{-0.19}

(c-3)^3=63.15789

c-3=\sqrt[3]{63.15789}

c=3+\sqrt[3]{63.15789}

c=6.98

If this function satisfies the Mean Value Theorem, then f must be continuous on  [1,7] and differentiable on (1,7).

But f is not continuous at x=3, hence this hypothesis of the Mean Value Theorem is contradicted.

 

3 0
3 years ago
What value of b will cause the system to have an infinite
m_a_m_a [10]

Answer:

b=6

Step-by-step explanation:

<u><em>The correct question is</em></u>

What value of b will cause the system to have an infinite number of solutions?

y = 6x – b

–3x + 1/2y = –3

we have

y=6x-b ----->equation A

-3x+\frac{1}{2}y=-3 -----> equation B

we know that

If the system has infinite number of solutions then, the equation A must be equal to the equation B

so

isolate variable y in the equation B

-3x+\frac{1}{2}y=-3

Multiply by 2 both sides

-6x+y=-6

y=6x-6 -------> new equation B

To find out the value of b, equate equation A and equation B

6x-b=6x-6

b=6

4 0
2 years ago
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