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3 years ago

What is the product?

Mathematics

2 answers:

Anton [14]3 years ago

6 0

Answer:

2x^2 +5x-3

Step-by-step explanation:

(x+3)(2x-1)

FOIL

first :(x*2x) = 2x^2

outer: x*-1 = -x

inner: 3*2x = 6x

last: -1 *3 = -3

Add together

2x^2 -x+6x-3

Combine like terms

2x^2 +5x-3

slavikrds [6]3 years ago

5 0

Answer:

The third option. 2x^2+5x-3.

Step-by-step explanation:

The product means to multiply them.

(x+3)(2x-1)

You don't multiply x to 2x and 3 and -1.

That is not the product and say it is 2x^2-3.

You have to multiply x to both 2x and -1.

You don't only multiply the terms that correspond with each other.

You have to do x times 2x and x times -1.

2x times x is 2x squared or 2x^2.

x times -1 is -x.

So you have 2x^2-x.

Leave that there for now.

Now, you have to multiply 3 with 2x and -1.

3 times 2x is 6x and 3 times -1 is -3.

Then you have 6x-3.

Bring back the 2x^2-x with the 6x-3.

Now you have 2x^2-x+6x-3.

You always have to simplify.

Combine like terms. -x plus 6x is 5x.

Therefore, you are left with 2x^2+5x-3.

That is the product of (x+3)(2x-1).

you can check by dividing the polynomials as well.

I hope this clarifies things!

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kow [346]

first off let's convert the mixed fractions to improper fractions.

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3 years ago

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Marina86 [1]

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2 years ago

Brainliest to first correct answer

Artyom0805 [142]

Answer:

Smallest surface area is of Cuboid B i.e 440 cm²

So, The company will choose cuboid B

Step-by-step explanation:

We need to find the surface area of all cuboids.

Surface Area of Cuboid A:

Length = 6

Breadth = 25

Height = 4

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2((6 \times 25)+(25 \times 4)+(6 \times 4))\\Surface \ Area \ of \ Cuboid=2(150+100+24)\\Surface \ Area \ of \ Cuboid=2(274)\\Surface \ Area \ of \ Cuboid=548\: cm^2$

So, Surface Area of Cuboid A = 548 cm²

Surface Area of Cuboid B:

Length = 10

Breadth = 6

Height = 10

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2(10 \times 6)+(6 \times 10)+(10 \times 10))\\Surface \ Area \ of \ Cuboid=2(60+60+100)\\Surface \ Area \ of \ Cuboid=2(220)\\Surface \ Area \ of \ Cuboid=440\: cm^2$

So, Surface Area of Cuboid B = 440 cm²

Surface Area of Cuboid C:

Length = 2

Breadth = 20

Height = 15

The formula used is: $Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)$

Putting values and finding surface area:

$Surface \ Area \ of \ Cuboid=2((Length\times Breadth)(Breadth \times Height)+(Length \times Height)\\Surface \ Area \ of \ Cuboid=2((2 \times 20)+(20 \times 15)+(2 \times 15))\\Surface \ Area \ of \ Cuboid=2(40+300+30)\\Surface \ Area \ of \ Cuboid=2(370)\\Surface \ Area \ of \ Cuboid=740\: cm^2$

So, Surface Area of Cuboid C = 740 cm²

So, We get:

Surface Area of Cuboid A = 548 cm²

Surface Area of Cuboid B = 440 cm²

Surface Area of Cuboid C = 740 cm²

The company wants to choose the design having smallest surface area.

So, smallest surface area is of Cuboid B i.e 440 cm²

So, The company will choose cuboid B

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3 years ago