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Neporo4naja [7]
3 years ago
8

What is 26% of 150?.?.?

Mathematics
2 answers:
hoa [83]3 years ago
8 0
Set up a proportion to solve
100% of 150 is 150
26% of 150 is x
so multiple 150 • 26 =3,900
then divide 3,900 by 100
you get 39
26% of 150 is 39
Alex73 [517]3 years ago
7 0

Answer:

39

Step-by-step explanation:

150 times .26 will give you 39

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Sergeu [11.5K]
l=2 \pi r
r=0.25 miles
l=2×\pi×0.25
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120(minutes)÷2(miles)=60(minutes per mile)
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8 0
3 years ago
Two cargo ships are sailing a direct course into harbor. Ship A is 22 miles from harbor. Ship Bis sailing into harbor on a cours
s344n2d4d5 [400]

Answer:

The distance of ship B from the Harbor is 32.26 miles

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.

I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.

cos(x) = \frac{adjacent}{hypotenuse}

cos(47) = \frac{22miles}{hypotenuse} .... flip both fractions.

\frac{1}{cos(47)} = \frac{hypotenuse}{22miles} .... multiply both sides by 22

\frac{22mi}{cos(47)} = hypotenuse

32.26mi = hypotenuse = B

So the distance of ship B from the Harbor is 32.26 miles

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

3 0
3 years ago
Watch it and tell me what u think
vesna_86 [32]

Answer:

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3 0
2 years ago
Read 2 more answers
Joe's final exam has true/false questions, worth 2 points each, and multiple choice questions, worth 5 points each. Let x be the
mixer [17]

This is the inequality

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3 years ago
Find the values of the variables for which ABCD must be a parallelogram
sleet_krkn [62]

Answer:

y=5 and x=4

Step-by-step explanation:

So,the diagonals of a parallelogram bisect each other..

therefore,we have our two eqn

4x-2=3y-1------------(i)

3y-3=3x

or,y-1=x----------(ii)

Now,simply substitute value of x in eqn (i)

4(y-1)-2=3y-1

or,4y-4-2=3y-1

or,y=5

Again,substitute y=5 in eqn (ii)

5-1=x

therefore,

x=5

Hope it helps you!!!

4 0
3 years ago
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