Answer:
You need to add: <span> <span>x2</span>+x+6</span>
Explanation:
Let the unknown part be represented by A
Then we have: <span> 3x−7+A=<span>x2</span>+4x−1</span>
Subtract <span>3x</span> from both sides
<span>−7+A=<span>x2</span>+4x−3x−1</span>
but <span>4x−3x</span> is giving:
<span>−7+A=<span>x2</span>+x−1</span>
Add 7 to both sides
<span>A=<span>x2</span>+x+6</span>
So you need to add: <span><span>x2</span>+x+<span>6</span></span>
The answer is I don’t know lol
Answer:
Triangle VTU and ABC are congruent by SAS
Step-by-step explanation:
You can tell that these triangles are the same because the lines on the sides and angle are the same.
Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.
<u>Step-by-step explanation:</u>
As given by the statement in the problem,
Q may be the middle point, which cut the diagonal PA into 2 equal halves.
In rhombus, diagonals meet at right angles.
which means that PQ = QA
x+2 = 3x - 14
Grouping the terms, we will get,
3x -x = 14+ 2
2x = 16
dividing by 2 on both sides, we will get,
x = 16/2 = 8
8+2 = 3(8) - 14 = 10 = PQ or QA
The form would be
y = -4x + 2