The equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1
<h3>Equation of a line</h3>
A line is the shortest distance between two points. The equation of a line in point-slope form and perpendicular to a line is given as;
y - y1 = -1/m(x-x1)
where
m is the slope
(x1, y1) is the intercept
Given the following
Point = (4, -1)
Line: 2x-y - 7 = 0
Determine the slope
-y = -2x + 7
y= 2x - 7
Slope = 2
Substitute
y+1 = -1/2(x -4)
Write in slope-intercept form
2(y + 1) = -(x - 4)
2y+2 = -x + 4
2y = -x + 2
y = -1/2 + 1
Hence the equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1
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Answer: 105.84 cm^2
To find the answer, first you have to start by finding the percent of the circle in the sector. Convert the radians given to 108 degrees. 108 out of 360 is 30%.
Now, find the area of the circle. It's pi x r^2, so the area is 352.810.
Multiply this by 30% to find our area of 105.84 cm^2
Density is the correct answer.
Answer: n = 4
Step-by-step explanation: you combine the like variables which turns it into
(4y - 3)
(4y - 3) is <em>another</em> way of saying ((4 x y) - 3)
So the 4 is turned into n making it (ny - 3)
