Question

Daniel wanted to know his approximate score on the final exam for his mathematics class. His professor hinted that his score was well above the class average. The professor announced that the mean for the class final exam was 90 with a standard deviation of 7. Given Daniel's z score of 1.67, what is the raw score for Daniel's exam grade?

Answer 1

Answer:   The raw score for Daniel's exam grade is 101.69.

Step-by-step explanation:

For x be any random variable.

Formula for z-score :

$z=\dfrac{x-\mu}{\sigma}$ , where $\mu$ = population mean

$\sigma$ = population standard deviation.

Let x be the raw score for Daniel's exam grade.

As per given , we have

$\mu=90$ , $\sigma=7$ and z= 1.67 , put these values in the above formula , we get

$1.67=\dfrac{x-90}{7}\\\\\Rightarrow\ x-90=7(1.67)=11.69\\\\\Righarrow\ x=11.69+90=101.69$

Hence, the raw score for Daniel's exam grade is 101.69.