The equation of the line would be
y = mx+b
where m is the slope, b is the y intercept.
<span>The line will form a triangular region in the first quadrant. Its area would be 1/2 base times height. The height is the y intercept
and the base is y intercept divided by slope. Therefore,</span>
A = b^2/2m
At point (2,5)
5 = 2m+b
Substitute that in the area
A = b^2/5-b
to find the least area, differentiate the area with respect to the height and equate it to 0
dA/db = 0
<span>find b and
use that to find m. Then, you can have the equation of the line.</span>
Answer:
(f⁻¹)'(b) = 1/f'(f⁻¹(b)) = 1/f'(a)
Step-by-step explanation:
The function f⁻¹(x) is the reflection of the function f(x) across the line y=x. Every point (a, b) that is on the graph of f(x) is reflected to be a point (b, a) on the graph of f⁻¹(x).
Any line with slope m reflected across the line y=x will have slope 1/m. (x and y are interchanged, so m=∆y/∆x becomes ∆x/∆y=1/m) Since f'(x) is the slope of the tangent line at (x, f(x)), 1/f'(x) will be the slope of the tangent line at (f(x), x).
Replacing x with f⁻¹(x) in the above relation, you get ...
... (f⁻¹)'(x) = 1/f'(f⁻¹(x)) will be the slope at (x, f⁻¹(x))
Putting your given values in this relation, you get
... (f⁻¹)'(b) = 1/f'(f⁻¹(b)) = 1/f'(a)
Is there a photo with this
Answer:-15 is correct
Step-by-step explanation:
(-6)-9 is the same as -6-9 since parenthesis aren’t really needed in thins case and if you use the order of operations you go left to right. So, -6-9=-15 because a negative- a negative= a negative.
