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tia_tia [17]
3 years ago
6

PLEASE HELP

Mathematics
1 answer:
Virty [35]3 years ago
4 0

<u>Answer-</u>

\boxed{\boxed{\dfrac{\widehat{BC}}{\widehat{DE}}=\dfrac{3}{4}}}

<u>Solution-</u>

We know that arc length is the product of radius and central angle in radian.

i.e \text{Arc length}=\text{Radius}\times \text{Central angle}

Here,

\theta_{BC}=1.18\ rad,\ \theta_{DE}=2.36\ rad\\\\AD=\dfrac{2}{3}AB\Rightarrow AB=\dfrac{3}{2}AD

So,

\dfrac{\widehat{BC}}{\widehat{DE}}=\dfrac{AB\times 1.18}{AD\times 2.36}

=\dfrac{\frac{3}{2}AD\times 1.18}{AD\times 2.36}

=\dfrac{3\times 1}{2\times 2}

=\dfrac{3}{4}

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In a series RL circuit, ET = 120 V, R = 40 Ω, and XL = 30 Ω. How much is EL?
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Firstly, we will draw

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ET = 120 V, R = 40 Ω, and XL = 30 Ω

Firstly, we will find current

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