Question

PLEASE HELP

Answer 1

Answer-

$\boxed{\boxed{\dfrac{\widehat{BC}}{\widehat{DE}}=\dfrac{3}{4}}}$

Solution-

We know that arc length is the product of radius and central angle in radian.

i.e $\text{Arc length}=\text{Radius}\times \text{Central angle}$

Here,

$\theta_{BC}=1.18\ rad,\ \theta_{DE}=2.36\ rad\\\\AD=\dfrac{2}{3}AB\Rightarrow AB=\dfrac{3}{2}AD$

So,

$\dfrac{\widehat{BC}}{\widehat{DE}}=\dfrac{AB\times 1.18}{AD\times 2.36}$

$=\dfrac{\frac{3}{2}AD\times 1.18}{AD\times 2.36}$

$=\dfrac{3\times 1}{2\times 2}$

$=\dfrac{3}{4}$