10 L of 30 % saline solution can be formed by mixing 4 L of 60 % saline solution and 6 L of 10 % saline solution.
Step-by-step explanation:
Let x be the number of liters of 60% saline solution
Now we require 10 L of 30% saline solution.
Liter soln % liters saline %
30 % 10 0.3
60 % x 0.6
10 % 10-x 0.1
Now forming the algebraic equation,
0.6x + 0.1 (10-x) = 10 (0.3)
0.6x + 1 - 0.1 x = 3
0.5 x = 2
x = 4 ( 4 l of 60 % solution is required. So 10 % saline solution required is 10 - 4 = 6 L).
Hence, 10 L of 30 % saline solution can be formed by mixing 4 L of 60 % saline solution and 6 L of 10 % saline solution.
Answer:
(-8,0)
Step-by-step explanation:
Solution:
<u>Simplify the equation and solve.</u>
- 89(54x − 36) + 2 = −34(−40 + 16x) + 90x
- => 4806x − 3204 + 2 = 1360 - 544x + 90x
- => 4806x = 1360 - 454x + 3202
- => 5260x = 4562
- => x = 4562/5260 = 2281/2630
The solution to the problem is 2281/2630.
Answer:
x = (-27)/11
Step-by-step explanation:
Solve for x:
(-11 x)/54 - 1/2 = 0
Put each term in (-11 x)/54 - 1/2 over the common denominator 54: (-11 x)/54 - 1/2 = (-27)/54 - (11 x)/54:
(-27)/54 - (11 x)/54 = 0
(-27)/54 - (11 x)/54 = (-11 x - 27)/54:
(-11 x - 27)/54 = 0
Multiply both sides of (-11 x - 27)/54 = 0 by 54:
(54 (-11 x - 27))/54 = 54×0
(54 (-11 x - 27))/54 = 54/54×(-11 x - 27) = -11 x - 27:
-11 x - 27 = 54×0
0×54 = 0:
-11 x - 27 = 0
Add 27 to both sides:
(27 - 27) - 11 x = 27
27 - 27 = 0:
-11 x = 27
Divide both sides of -11 x = 27 by -11:
(-11 x)/(-11) = 27/(-11)
(-11)/(-11) = 1:
x = 27/(-11)
Multiply numerator and denominator of 27/(-11) by -1:
Answer:x = (-27)/11
Answer:
V=(πr^2 x h)/3
lets use π as 3.14 cause I dont know what pi u using
3.14 x 4^2 x 15 = 753.6/3 = 251.2
If you're using π as your pi, than just replace 3.14 by π on calculator
Hope that answers your question