Question

PLEASE HELP ASAP

Answer 1

Answer:

Part A: (2x−5)(x+2)

Part B: (5/2,0) and (-2,0)

Part C: The graph of f(x) has both "ends" of the graph pointing upward. You can describe this as heading toward infinity.

Part D: To graph function we can use x-intercepts and "ends" to sketch.In order to graph better use one more point of parabola that you can find as the average of x-intercepts: (-2+5/2)/2 =1/4.This is just x coordinate and you need to plug in 1/4 in the f(x) and find y coordinate -10 1/8. You can use y-intercept (0,-10) as well to graph.

Step-by-step explanation:

Part A:  $2x^{2} -x-10 =(2x - 5)(x+2)$

What 2 numbers when multiplied give -20 and when added up -1. Numbers are -5 and 4.

Rewrite quadratic expression as $2x^{2} -5x +4x -10$

Factor by grouping $x(2x-5)+2(2x-5)$

$(2x-5)(x+2)$

Part B: x- intercepts are found when (2x−5)(x+2) = 0

Set factors equal to 0.

2x−5=0 or x+2=0

x=5/2 or x=−2

Part C: The lead coefficient (multiplier on the $x^{2}$) is a positive number, which causes the parabola to open upward.The first graph of $y= 2x^{2} -x-10$ has both "ends" of the graph pointing upward so  this can be described as heading toward infinity.

Part D:

Answer 2

Answer:

Do you want me to do the answer and work it or just the answer

Step-by-step explanation: