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Anni [7]
3 years ago
7

Five times the sum of a number and 4 is 9

Mathematics
1 answer:
Mazyrski [523]3 years ago
6 0

Answer:

5x+4=9

Step-by-step explanation:

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The annual rainfall in a certain region is approximately normally distributed with mean 41.8 inches and standard deviation 5.8 i
kicyunya [14]
I believe the answer would be B
8 0
3 years ago
Please help it’s due today
alexandr402 [8]

Answer:

Angle <u>A</u><u> </u>= 15°

use angle properties of triangle to solve this.

7 0
3 years ago
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Which is equivalent to sqrt x^10<br> A. X-5<br> B. X -1/5<br> C. X sqrt 10<br> D. X 1/5<br> E. X^5
Lesechka [4]
<h3>Answer:  E) x^5</h3>

\sqrt{x^{10}} = x^5

=====================================================

Explanation:

We simply take half of the exponent 10 to get 5. This applies to square roots only.

So the rule is \sqrt{a^b} = a^{b/2}

A more general rule is

\sqrt[n]{a^b} = a^{b/n}

If n = 2, then we're dealing with square roots like with this problem. In this case, a = x and b = 10.

5 0
3 years ago
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A ball is thrown upward from the top of a 40 foot high building at a speed of 80 feet per second. The ball's height above
tekilochka [14]

it takes 5 seconds to reach a height of 40 ft. and It takes 2.5 seconds to reach maximum height.

Let h(t) represent the height of the ball at time t.

Given that the height is given by:

h(t) = -16t² + 80t + 40

1) For the ball to reach a height 0f 40 ft, h(t) = 40, hence:

40 = -16t² + 80t + 40

16t² - 80t = 0

t(t - 5) = 0

t = 0 or t = 5

Hence it takes 5 seconds to reach a height of 40 ft.

2) The maximum height is at h'(t) = 0,

h'(t) = -32t + 80

-32t + 80 = 0

32t = 80

t = 2.5

It takes 2.5 seconds to reach maximum height.

Find out more at: brainly.com/question/11535666

5 0
2 years ago
Adam and Tom share a sum of money in the ratio 18:17
Digiron [165]

x = total amount split between Adam and Tom.

since we know the total amount split between both in a 18 : 17 ratio is "x", let's divide "x" by (18 + 17) and distribute accordingly to get the amount of each.

\stackrel{Adam~received}{18\cdot \cfrac{x}{18+17}}\qquad \qquad \stackrel{Tom~received}{17\cdot \cfrac{x}{18+17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{since we know that Adam got "5" more}}{ \stackrel{Adam}{18\cdot \cfrac{x}{18+17}}~~ = ~~\stackrel{Tom}{17\cdot \cfrac{x}{18+17}~~ + ~~5} }\qquad \implies \qquad \cfrac{18x}{35}~~ + ~~\cfrac{17x}{35}+5

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{35}}{35\left( \cfrac{18x}{35} \right)~~ = ~~35\left( \cfrac{17x}{35}+5 \right)}\implies 18x~~ = ~~17x+175\implies \boxed{x =175} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{Tom~received}{17\cdot \cfrac{x}{18+17}}\implies \cfrac{17(175)}{35}\implies \blacktriangleright 85 \blacktriangleleft

5 0
2 years ago
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