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omeli [17]
2 years ago
6

Find two positive numbers satisfying the given requirements. The product is 432 and the sum of the first plus three times the se

cond is a minimum.
Mathematics
1 answer:
kogti [31]2 years ago
4 0

Answer:

<h3>36 and 12</h3>

Step-by-step explanation:

Let the two positive integers be x and y.

If their product is 432, then

xy = 432 ......... 1

Also if the sum of the first plus three times the second is a minimum, then;

p(x) = x + 3y

From 1;

y = 432/x ..... 3

Substitute 3 into 2;

p(x) = x+3y

p(x)= x + 3(432/x)

p(x) = x + 1296/x

Since the expression is at minimum when dp(x)/dx = 0

dp/dx = 1 + (-1296)/x²

dp/dx = 1  -1296/x²

0 =  1  -1296/x²

0 = (x²-1296)/x²

cross multiply

0 = x²-1296

x² = 1296

x = √1296

x = 36

Since xy = 432

36y = 432

y = 432/36

y = 12

Hence the two positive numbers are 36 and 12

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What are the steps to solve for: 1/5(x+5)=1/4(x-3)+1
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1+ \frac{x}{5} = \frac{1}{4} (x-3)+1

Step 3. Simplify \frac{1}{4} (x-3) to \frac{x-3}{4}

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3 0
3 years ago
A store manager predicts that 115 hats will be sold if each hat costs $18. The manager predicts that 3 less hats will be sold fo
8_murik_8 [283]

Answer:

The prices at which manager predict that at least 55 hats will be sold would be would be of $38

Step-by-step explanation:

According to the given data we the following:

Number of hats sold at $18=115

The manager predicts at 3 less will sold for every rise in 1 $ for at least 55 hats.

Therefore, reduction in number=115 hats-55 hats=60

So, increase in price=reduction in number/number of hats manager predicts that  will be sold for every $1 increase in price

increase in price=60/3=$20

Therefore, prices at which manager predict that at least 55 hats will be sold would be=$18+$20=$38

The prices at which manager predict that at least 55 hats will be sold would be would be of $38

8 0
3 years ago
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