A survey taken during class revealed 30% of the students in a class bring their lunch to school. If the probability that a rando
mly selected student is a boy given that the student brings their lunch is 40%, what is the probability that a randomly selected student will be a boy that brings his lunch to school?
For the answer to the question above asking <span>what is the probability that a randomly selected student will be a boy that brings his lunch to school? I'll provide a solution for the following problem below. </span>P(boy |lunch) = P(boy and lunch)/P(lunch) = 0.40 P(boy and lunch) = P(lunch)*0.4 = 0.3*0.4 = 0.12
Since 1 pound is 16 ounces, you would convert the 2 pounds to 32 ounces (16+16) and add the 32 ounces to the already given 9 ounces to get 41 ounces. (32+9) Hope that helped.
