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weeeeeb [17]
3 years ago
8

For math I need to: Add. 1/3+1/9

Mathematics
2 answers:
Radda [10]3 years ago
8 0
The answer is 4 over 10 because u just add the tops so u add 1 plus 3 which is 4 and then u add 1 plus 9 which is 10 so 4 over 10 hope that helped!!!
chubhunter [2.5K]3 years ago
4 0
<span>=<span>49</span></span><span>(Decimal: 0.444444)</span>
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The combined area of two squares is 45 square centimeters.each side of one square is twice as long as the side of the other .wha
serg [7]
Formula of square area
a = s²
thus, area of the first square could be written as s₁² and area of the second square could be written as s₂²

First, write an expression in the form of equation system
An expression for "The combined area of two squares is 45 square centimeters" is:
⇒ s₁² + s₂² = 45 <em>(first equation)</em>
An expression for "Each side of one square is twice as long as side of the other" is:
⇒ s₁ = 2s₂ <em>(second equation)</em>

Second, solve the equation system by substitution method.
⇒ We could substitute 2s₂ to s₁ (second equation) in the first equation in order to find the value of s₂
s₁² + s₂² = 45
(2s₂)² + s₂² = 45
(2²)(s₂)² + s₂² = 45
4s₂² + s₂² = 45
5s₂² = 45
s₂² = 45/5
s₂² = 9
s₂² = 3²
s₂ = 3

⇒ Substitute the value of s₂ to the second equation in order to find the value of s₁
s₁ = 2s₂
s₁ = 2(3)
s₁ = 6

The length of each side of the larger square is 6 centimeters
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In right triangle ABC shown below, what is the length of BC?
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I’m pretty sure it’s 6
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.When you started your homework assignment, your friend already had 6 exercises done.
stiv31 [10]

Answer: 6 minutes

Step-by-step explanation:

5 0
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10.6ft times 9.28ft =
Margaret [11]
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4 0
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Read 2 more answers
A dormitory has n students, all of whom like to gossip. one of the students hears a rumor, and tells it to one of the other n −
Alekssandra [29.7K]

Answer:

P(r)=\frac{(n-3)(n-4)....(n-r)}{(n-2)^{r-2}}

Step-by-step explanation:

From the question, we have the following condition:

p_1=p_2=1,\:and\:p_n=0

We know that each student who hears the rumor tells it to a student picked at random from the dormitory (excluding, of course, himself/herself and the person from whom he/she heard the rumor)

The 3rd student can therefore tell the rumour to n-2 students but only n-3 will accept it.

\implies p(3)=\frac{n-3}{n-2}

Consequently, the 4th student must not tell the 1st and second students.

\implies p(4)=\frac{n-3}{n-2}\times \frac{n-4}{n-2}

We can rewrite this to observe a pattern:

\implies p(4)=\frac{(n-3)(n-4)}{(n-2)^2}

\implies p(4)=\frac{(n-3)(n-4)}{(n-2)^{4-2}}

\implies p(r)=\frac{(n-3)(n-4)(n-5)...(n-r)}{(n-2)^{r-2}}

Hence, the probability that the rumor is told r times without coming back to a student who has already is:

P(r)=\frac{(n-3)(n-4)....(n-r)}{(n-2)^{r-2}}

See attachment for complete question

4 0
3 years ago
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