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Minchanka [31]
4 years ago
10

If function h has an inverse and h^-1(1) = -5, find h(-5)

Mathematics
1 answer:
Olegator [25]4 years ago
3 0

Answer:

h(5) = 1

Step-by-step explanation:

if h(x) = y then x = h^-1(y)

in other words.

h^-1(h(x))=x

given that,

h^-1(1) = -5

h(h^-1(1)) = h(5)

1 = h(5)

or, if you want,

  • h takes x and maps it to y
  • h^-1 takes y and maps it back to x
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What is the answer to 2(3x-4)-5=-7
kozerog [31]

Answer: x = 1

Step-by-step explanation:

1) Reorder the terms:

2(-4 + 3x) + -5 = -7

(-4 * 2 + 3x * 2) + -5 = -7

(-8 + 6x) + -5 = -7

2) Reorder the terms:

-8 + -5 + 6x = -7

3) Combine like terms: -8 + -5 = -13

-13 + 6x = -7

4) Solving

-13 + 6x = -7

5) Solving for variable 'x'.

6) Move all terms containing x to the left, all other terms to the right.

7) Add '13' to each side of the equation.

-13 + 13 + 6x = -7 + 13

8) Combine like terms: -13 + 13 = 0

0 + 6x = -7 + 13

6x = -7 + 13

9) Combine like terms: -7 + 13 = 6

6x = 6

10) Divide each side by '6'.

x = 1

11) Simplifying

x = 1

4 0
3 years ago
The Verrazano Narrows Bridge has a main span of 3,260 feet. The Akashi Kaikyo Bridge has a main span that is about 54% longer. W
zloy xaker [14]

Answer:

Rounding it to the nearest foot, the length of the main span of the Akashi Kaikyo Bridge is 5,020 feet.

Step-by-step explanation:

Given that the Verrazano Narrows Bridge has a main span of 3,260 feet, while the Akashi Kaikyo Bridge has a main span that is about 54% longer, to determine the length of the main span of this last bridge, the following calculation must be performed:

3,260 x 1.54 = X

5,020.4 = X

Thus, rounding it to the nearest foot, the length of the main span of the Akashi Kaikyo Bridge is 5,020 feet.

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Answer:

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Step-by-step explanation:

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So,

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7.5 as fraction = 7 1/2 or 15/2

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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