Answer:
-(x+14)/2
Step-by-step explanation:
There is a website that automatically calculates this for you.
Check it out, its called symbolab
The function:
f ( x ) = x * 0.965^t
where x is the initial amount and t is the number of the years
80 = x * 0.965^3
80 = x * 0.89632
x = 80 : 0.89632 ≈ 89
Answer:
The initial amount of animals was 89.
Answer:
50 years
Step-by-step explanation:
the answer is 50 years bc 2% of 3000 is 60 and to get to 300 from 60 you would multiply by 50 to get 3000 added to the populationg colorado has now you get 6000.
brainliest pls
That is a difference of two square numbers, we can factorize them easily:
<span>0 =-b^2 + 25
b^2 - 25 = 0
(b + 5)(b - 5) = 0</span>
I find it easier to start from scratch and write out the equations, then compare them with the given equations.
Let m and j represent the ages of the two boys. Then m-5=(2/3)(j-5)
Also, in ten years: m+10 = (5/6)j.
Let's solve this system: Mult the first eqn by 3 to remove the fraction:
3(m-5) = 2(j-5), or 3m - 15 = 2j -10. Next, mult. the 2nd eqn by 6 to remove the fraction: 6m+60 = 5j.
Our two equations are (at this point) 3 m - 15 = 2j - 10 and
6m +60 = 5j
Let's mult. the first equation by -2, so as to obtain the coefficient -6 for m:
-6m + 30 = -4j + 10
6m + 60 = 5j
---------------------------
90 = j + 10, so j = 80 (wow!)
Let's now find m: 6m + 60 = 5(80), or 6m = 400+60 = 460
Then m = 76 2/3.
We must check our solution (m = 76 2/3, j = 80):
Let's subst. these values into m-5=(2/3)(j-5)
Does 76 2/3 - 5 = (2/3)(80) - 10/3?
Does 76 2/3 - 15/3 = 160/3 - 10/3?
Does 76 - 15 = 160 - 10 No. So something's wrong here.
Going back to the problem statement:
<span>x-5=2/3(y-5) and x+10=5/6(y+10) seems correct!
Mike's age 5 years ago was x-5, and james' age 5 years ago was y-5. The multiplier (2/3) is also correct.
Mikes age 10 years from now will be x+10, and james' y+10.
The first answer set is the correct one.</span>
