Let f(x) =y be another equation
where the slope of f(x) =y cannot be 4/5, can it be other quation
Answer:
f(x) = (x+6)² - 10
Step-by-step explanation:
To write the equation in vertex form we, we need to use completing square method.
f(x) = x²+ 12x + 26 = (x² + 2*x*6 + 6²) - 6² + 26 = (x+6)² -36 + 26 =
= (x+6)² - 10
f(x) = (x+6)² - 10
1. Pick two points on the line and determine their coordinates.
2. Determine the difference in y-coordinates of these two points (rise).
3. Determine the difference in x-coordinates for these two points (run).
4. Divide the difference in y-coordinates by the difference in x-coordinates (rise/run or slope).
Answer: ∠OZP = 62 ∠PZQ = 63
<u>Step-by-step explanation:</u>
Use the Angle Addition Postulate
∠OZP + ∠PZQ = ∠OZQ
(4r + 2) + (5r - 12) = 125
9r - 10 = 125
9r = 135
r = 15
∠OZP = 4r + 2
= 4(15) + 2
= 60 + 2
= 62
∠PZQ = 5r - 12
= 5(15) - 12
= 75 - 12
= 63
Answer:
a. Infinitely many solutions
Step-by-step explanation:
The given equations are 2x - y = 3
4x = 6 + 2y
We can use substitution method to solve these system of equations.
2x - y = 3
y = 2x - 3
Now plug in y = 2x - 3 in the second equation, we get
4x = 6 + 2(2x - 3)
4x = 6 + 4x - 6
4x = 4x
Here we get infinitely many solution.
Both the equations are the same.
Thank you.
