3 years ago

Which of the following facts would be sufficient to

Mathematics

1 answer:

Nady [450]3 years ago

4 0

[email protected] = bainegoudy666 the answer is abbca

You might be interested in

Please answer will mark branliest

Flauer [41]

Step-by-step explanation:

5 tank tops= $20

5 t-shirts= $35

20/5= 4

35/5=7

7-4=3

The t-shirts are $3 more than the tank tops

4 0

3 years ago

Order these numbers from Least to Greatest 4,209 2,438 4,703 3,026

Virty [35]

2,438 3,026 4,209 4,703

7 0

4 years ago

a particle moves along the y-axis with a motion defined by the equation s(t)=lnt/t for t>0. Find the velocity at t=2

aliina [53]

The velocity would be 0.3466

5 0

4 years ago

Please help<br>step by step<br>Parentheses, Braces, and Brackets

AURORKA [14]

Answer:

sorry iuuytffsa at tfyui0

3 0

3 years ago

Find the simplified product b-5/2b x b^2+3b/b-5

White raven [17]

Answer:

The product $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}$

Step-by-step explanation:

Given expression $\frac{b-5}{2b}$ and $\frac{b^2+3b}{b-5}$

We have to find the product of $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}$

Consider the given expression $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}$

Multiply fractions, we have,

$\frac{a}{b}\cdot \frac{c}{d}=\frac{a\:\cdot \:c}{b\:\cdot \:d}$

$=\frac{\left(b-5\right)\left(b^2+3b\right)}{2b\left(b-5\right)}$

Cancel common factor ( b - 5 )

we have, $=\frac{b^2+3b}{2b}$

Apply exponent rule,

$\:a^{b+c}=a^ba^c$

$b^2=bb$

$=bb+3b=b(b+3)$

$=\frac{b\left(b+3\right)}{2b}$

Cancel common factor b , we have,

$=\frac{b+3}{2}$

Thus, the product $\frac{b-5}{2b}\times\frac{b^2+3b}{b-5}=\frac{b+3}{2}$

8 0

3 years ago

Read 2 more answers