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RoseWind [281]
3 years ago
12

The length of one leg of a right triangle is 11 and the length of the hypotenuse is 29. Find the length of the missing leg to th

e nearest hundredth.
Mathematics
1 answer:
VladimirAG [237]3 years ago
6 0

Step-by-step explanation:

Let the missing leg or side is x

By Pythagoras theorem

29²=11²+x²

x=√(29²-11²)

x=26.83

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Question 8 simplify 4a 2 - 3a - 4 1. 7a - 7 2. a - 2 3. a 6 4. 6a - 2
Viktor [21]
Not Specific Enough:
is it 4a(2-3a)-41(7a-72)-23a(64)6a-2? 
8 0
3 years ago
How to find the legs of a right triangle with only the hypotenuse?
GuDViN [60]

Let x = legs of right triangle.

The set up would be:

x^2 + x^2 = (hypotenuse)^2

Understand?

8 0
3 years ago
2( 10 - a^2 ) + 7a If ( a = 4 )Evaluate each expression
Lostsunrise [7]

Solution:

Given:

2(10-a^2)+7a

when a = 4, substitute for a in the expression;

\begin{gathered} 2(10-a^2)+7a=2(10-4^2)+7(4) \\ =2(10-16)+28 \\ =2(-6)+28 \\ =-12+28 \\ =16 \end{gathered}

Therefore, if (a = 4), then

2(10-a^2)+7a=16

Hence, the answer is 16.

6 0
1 year ago
Please answer it now in two minutes
makkiz [27]

Answer:

VX = 8.8 in

Step-by-step explanation:

By applying Sine rule in the right triangle WXV,

Sin(∠W) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

             = \frac{\text{VX}}{\text{WX}}

Sin(34)° = \frac{VX}{15}

VX = 15.Sin(34)°

     = 8.8379

     ≈ 8.8 in.

Therefore, measure of side VX is 8.8 in.

6 0
3 years ago
Given: Circle O with diameter LN and inscribed angle LMN Prove: is a right angle. What is the missing reason in step 5? Statemen
ZanzabumX [31]

Answer:

Inscribed angle theorem

Step-by-step explanation:

This theorem states that an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle.

In this case, the angle is ∠LMN and the arc is arc LN. Arc LN measures 180°,  because segment LN is the diameter of the circle. Then, by the theorem:

∠LMN = (1/2)*arc LN = (1/2)*180° = 90°

3 0
3 years ago
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