The value of the population of the growth of an endangered birth after 5 years is 1975
<h3>How to determine the population after 5 years?</h3>
The population function is given as:
B(t) = 100 + 3/5t^5
At 5 years, the value of t is 5
So, we have
t = 5
Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5
This gives
B(5) = 100 + 3/5 * 5^5
Evaluate the exponent
B(5) = 100 + 3/5 * 3125
Evaluate the product
B(5) = 100 + 1875
Evaluate the sum
B(5) = 1975
Hence, the value of the population of the growth of an endangered birth after 5 years is 1975
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Answer:
Step-by-step explanation:
Answer:
the answer is B. (15,4) :
Step-by-step explanation:
By representing the equation is written in the form y = ax + b .
The value of b is 8.
According to the question
A start-up company opened with 8 employees.
So, Number of employees = 8
At zero quarter = 8
The company’s growth plan assumes that 2 new employees will be hired each quarter
After 1 quarter = Number of employees + 2 new employees
After one quarter = 8 + 2 = 10
Equation is written in the form y = ax + b to represent the number of employees, y, employed by the company x quarters after the company opened
y = ax + b
10 = 2 × 1 + b
10 = 2 + b
Subtract 2 on both sides of the equation
b = 10 - 2
b = 8
The value of b is 8.
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Answer with explanation:
Equation of Linear Regression line is
y=1.14 x + 3.805
A line of regression is that line which passes through none of the points, few points or all the points in the two dimensional coordinate plane.It tells value of one variable when another variable is known.
for, x=30
y=1.14 × 30 +3.805
y=34.20 +3.805
y=38.005
y=38 (approx)
So, Ordered pair is , (30,38)
Option B
