Answer:
the third option. x is a real number
The value of
- m∠PQS = 71°
- m∠PQT = 142°
- m∠TQR = 41°
Given
SQT = (8x₋25) and PQT = (9x₊34)
SQR = 112°
we need to find the x angle and the remaining angles.
we know that QS bisects ∠PQT
⇒ 2(8x₋25)° = (9x₊34)°
(16x ₋ 30)° = (9x₊34)°
16x ₋ 9x = 34 ₋ 30
x = 12°
substitute x value in the given values of angles.
m∠PQS = (8x ₋ 25)° = (8(12)₋25) = 71°
m∠PQT = (9(12)₊34) = 142°°
m∠TQR = 112° ₋ ∠PQS = 112° ₋ 71° = 41°
hence we get the desired angles from the given angles.
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-7 = 2x + 8
Solve for x. First subtract 8 to both sides.
-7 - (8) = 2x + 8 - (8)
-15 = 2x
Divide by 2.
-15/(2) = -2x/(2)
x = -15/2 = -7.5