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3 years ago

What is the slope of a linear that is perpendicular to the line y=-1/2x+5?

Mathematics

1 answer:

Vlada [557]3 years ago

6 0

Step-by-step explanation:

Equation of given line is:

$y = - \frac{1}{2} x + 5 \\ \\ equating \: it \: with \: y =m_1x + c \\ we \: find \: \\ m_1 = - \frac{1}{2} \\ let \: m_2 \: be \: the \: slope \: of \: required \: line \\ \\ \therefore \: m_1 \times m_2 = - 1( \because \: lines \: are \: \perp) \\ \\ \therefore \: - \frac{1}{2} \times m_2 = - 1\\ \\ \therefore \: m_2 = 2 \\$

Thus, the slope of required line is 2.

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Can anyone please help with this

CaHeK987 [17]

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Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12<br> a + 2b - d = ?

Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

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3 years ago

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<h3>Answer: 3 units</h3>

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Explanation:

The y coordinates are identical, so we just need to focus on the x coordinates.

Going from 0 to -3 is a distance of 3 units. Drawing out a number line might help.

Or we could apply subtraction and absolute value

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The absolute value is to ensure the result is never negative. Distance is never negative.

Side note: if the y coordinates weren't the same, then we'd have to use either the pythagorean theorem or the distance formula.

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What is the slope of a linear that is perpendicular to the line y=-1/2x+5?​

What is the slope of a linear that is perpendicular to the line y=-1/2x+5?