Question

HELP!! Drag values to complete each equation.

Answer 1

Answer:

a.$((12)^2)^3\cdot (12)^{-4}=12^2$

b.$\frac{(12)^7\cdot (12)^{-5}}{(12)^2}=1$

Step-by-step explanation:

We have to complete each equation

We are given that

$((12)^2)^3\cdot (12)^{-4}$

$(12)^6\cdot (12)^{-4}$

Using identity

$(a^x)^y=a^{xy}$

$(12)^{6-4}=(12)^2$

Using identity: $a^x\cdot a^y=a^{x+y}$

$((12)^2)^3\cdot (12)^{-4}=12^2$

b.$\frac{(12)^7\cdot (12)^{-5}}{(12)^2}$

$\frac{(12)^2}{(12)^2}$

$(12)^{2-2}=(12)^0=1$

Using identity: $\frac{a^x}{a^y}=a^{x-y},a^0=1$

$\frac{(12)^7\cdot (12)^{-5}}{(12)^2}=1$

Answer 2

(12²)³ x 12^-4 = 144 which means it is 12² = 144.

12^7 x 12^-5 / 12² which equals 1.

Hope this Helps!!