<u>Problem</u>
A bag contains 6 blue marbles, 10 red marbles, and 9 green marbles. If two marbles are drawn at random without replacement, what is the probability that two red marbles are drawn?
<u>Work </u>
Probability = no. of favorable outcomes /total no. of outcomes
Probability of getting a blue marble=5/5+6+9=5/20
Probability of getting a red marble=6/20−1=6/19
5/20×6/19
<u>Answer</u>
3/20
So it is C.
Answer:
11.6 should be your answer!
Step-by-step explanation:
Im so sorry if its wrong!
Hope this helps!!
( > .< )
Answer:
No, it is not.
Step-by-step explanation:
comparing the two given values, 1.75 and 6, estimating 1.75 for 6 is not reasonable. This is due to the fact that converting 1.75 to the nearest whole number gives 2 which is far away from 6. Since,
6 - 2 = 4
So, estimating 1.75 for 6 would involve a large value of error. Which make it unreasonable. It would have been more reasonable to estimate 1.75 for 2.
Tbh i’m just trying to get points
Answer:
Equation: y(1.09)^x
After 10 years there will be about 12 squirrels.
Step-by-step explanation:
y(1.09)^x
=5(1.09)^10
=(approx.) 12 squirrels
