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Virty [35]
3 years ago
15

You flip a coin 3 times. What is the probability that it comes up heads all three times (HHH)?

Mathematics
1 answer:
Volgvan3 years ago
5 0

Answer:

1 out of 8

Step-by-step explanation:

If you flip a coin there are eight possible outcomes:

HHH

HHT

HTT

TTT

THH

TTH

THT

HTH

SO the probability of getting all heads is 1 over 8.

Hope this helps

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The Lagrangian is

L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)

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L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}

L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda

L_\lambda=x^2+y^2-9=0

Substitute x,y into the last equation and solve for \lambda:

\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6

Then we get two critical points,

(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)

We get an absolute maximum of 3\sqrt{17}\approx12.369 at the second point, and an absolute minimum of -3\sqrt{17}\approx-12.369 at the first point.

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Answer:

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Mashutka [201]
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