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Ede4ka [16]
3 years ago
13

Combine the like terms to create an equivalent expression: r+(−5r)

Mathematics
1 answer:
nevsk [136]3 years ago
8 0

Answer:

-4r

Step-by-step explanation:

Since r and -5r both have the same variable, we can combine them

r-5r = -4r

r+(−5r) = -4r

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Which descriptions about simple interest and yearly compounded interest are true? Check all that apply. Only compound interest h
pychu [463]

Answer:

  • Only compound interest has an exponent in its formula.
  • Simple interest is only earned on the original principal investment.
  • Compound interest is earned on principal and interest.

Step-by-step explanation:

The above statements are self-explanatory.

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The one statement that can be argued is ...

  "Compound interest earns more money than simple interest at the same rate for the same amount of time."

This is true for time periods <em>longer than the initial compounding interval</em>. If interest is compounded annually, the amount of simple interest and compound interest <em>will be the same for the first year</em>. After that, the compound interest account earns more, because interest is paid on interest and principal, not just principal.

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3 years ago
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Evaluate Y=3x-5 when x=6
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3 years ago
Question in attachment
ELEN [110]

Answer:

  • $20,000 at 8.5%
  • $10,000 at 10%

Step-by-step explanation:

There are a number of ways to solve mixture problems like this. Some are simple enough you can almost write down the answer. One I like uses a diagram to help you find the ratios of the components of the mix. You can do the same thing with a formula (without the diagram).

The basic idea is that you compute a ratio between two differences. The numerator is the difference between the average interest rate and the lower interest rate. Here, the average interest rate is 2700/30,000 = 0.09 = 9%. Then the numerator is 9% -8.5% = 0.5%

The denominator is the difference between the two interest rates of the investments: 10% -8.5% = 1.5%. And the ratio of these two values is ...

  0.5%/1.5% = 1/3

This is the fraction of the total investment that was invested at the higher interest rate:

  (1/3)×$30,000 = $10,000 . . . . was invested at 10%

Then the remaining amount, $20,000, was invested at 8.5%.

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If you would prefer an equation, you can let x represent the amount invested at the higher rate. (That is the most convenient assignment of variables, as it keeps all of the numbers positive.) Then (30,000 -x) is the amount invested at the lower rate. The total amount of interest is ...

  10%(x) +8.5%(30,000 -x) = 2700

  x(10% -8.5%) = 2700 -8.5%(30000) . . . . . subtract 8.5%(30,000)

  x = (2700 -8.5%(30,000))/(10% -8.5%) . . . . divide by the coefficient of x

We have purposely left the expression unevaluated so that you can compare it to the math we described above. If you factor out 30,000 from the numerator of this fraction, you see the ratio that we described in words:

  x=30000\left(\dfrac{\dfrac{2700}{30000}-8.5\%}{10\%-8.5\%}\right)\\\\x=10,000

This tells us $10,000 was invested at 10%, and $20,000 was invested at 8.5%.

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Answer:

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The domain would be (negaive infinity, positive infinity)

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