9414 1404 393
Answer:
$1.80, 2.90, 4.00, 10.90
not proportional
Step-by-step explanation:
For some distance d, we have a charge f(d) that is ...
![f(d)=\begin{cases}1.00&0\le d\le0.1\\1.00+0.10\cdot\dfrac{(d-0.1)}{0.10}&0.1](https://tex.z-dn.net/?f=f%28d%29%3D%5Cbegin%7Bcases%7D1.00%260%5Cle%20d%5Cle0.1%5C%5C1.00%2B0.10%5Ccdot%5Cdfrac%7B%28d-0.1%29%7D%7B0.10%7D%260.1%3Cd%5Cend%7Bcases%7D)
for d > 0.1, this simplifies to d +0.9.
Then the charges are ...
![\begin{array}{cc}\underline{\text{miles}}&\underline{\text{charge}}\\9/10&1.80\\2&2.90\\3\ 1/10&4.00\\10&10.90\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcc%7D%5Cunderline%7B%5Ctext%7Bmiles%7D%7D%26%5Cunderline%7B%5Ctext%7Bcharge%7D%7D%5C%5C9%2F10%261.80%5C%5C2%262.90%5C%5C3%5C%201%2F10%264.00%5C%5C10%2610.90%5Cend%7Barray%7D)
The different relation for the first 1/10 mile indicates ...
the relationship is not proportional.
Answer:
Student ticket: $2
Adult ticket: $5
Step-by-step explanation:
1. Setting up the system of equations
let x be the cost for a child
let y be the cost for an adult
For the monday, that would be:
33x + 42y = 276
For the tuesday, you ahve
46x + 40y = 292
2. Solving
First, simplify each equation
33x + 42y = 276
To get all the numbers smaller divide both sides by 3
11x + 14y = 92
Do the same for the other equation:
46x + 40y = 292
divide both sides by 2
23x + 20y = 146
You want to use elimination, so take the equation 11x + 14y = 92 and multiply both sides by 10
110x + 140y = 920
Take the equation 23x + 20y = 146 and multiply both sides by 7
161x + 140y = 1022
Subtract the two equations:
110x + 140y = 920
- (161x + 140y = 1022)
-51x = -102
divide both sides by -51
x = 2
Plug this into the original equation, 11x + 14y = 92:
11 * 2 + 14y = 92
22 + 14y = 92
subtract 22 from both sides
14y = 70
divide both sides by 14
y = 5
So the cost of a student ticket is $2 and the cost of an adult ticket is $5
Answer:
A
Step-by-step explanation:
equation is of the form f(x) - a which implies a translation downwards of a units
width: x/2, Length:x
18=x(x/2), 18=x^2/2, 36 = x^2, x= -6,6 Use the positive value of 6 for x. the width will be 6/2=3.
29.3 mph because the first bicyclist went 88 miles while the second went only 84 at 28 mph