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kiruha [24]
3 years ago
8

The price of a lawn mower is x dollars. The store is having a 75% end of summer clearance sale. Which expression can be used to

find the clearance price of the mower?
Mathematics
2 answers:
Marrrta [24]3 years ago
6 0

Answer:

A

Step-by-step explanation:

.25x

100% - 75% = 25%

The clearance price is 25% of the price of the lawn mower.

Write 25% as a decimal and multiply.

.25x

PilotLPTM [1.2K]3 years ago
6 0

Answer:

0.25x

Step-by-step explanation:

The price of a lawn mower is x dollars.

The store is having a 75% end of summer clearance sale.

So, clearance rate = 100% - 75 % = 25 %

So,  the clearance price of the mower = 25\% \times x

                                                                = \frac{25}{100} \times x

                                                                = 0.25x

So, expression can be used to find the clearance price of the mower is 0.25x

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aniked [119]

#a

m<5=40°

  • Reason-Its Given

#b

m<2=140

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#c

<5 and <2 are linear pair(looked properly in diagram) Hence they are supplementary.

#d

<5 and 2 are same side interior angles (Clearly shown on diagram .

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#e

a||b

Let's verify

Let the angle below <1 be <3

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<2+<3=180

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\\ \sf\longmapsto

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If Isabella runs 23 mile each day, how many miles will Isabella run in 6 days?
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What percentage of 128 is 96?
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Determine the equation of the circle graphed below.
sergij07 [2.7K]

Answer:

Equation = (x - 6 )² + ( y + 3 )² = 9

Step-by-step explanation:

The circle passes through ( 6, 0) and  ( 6 , -6)

They are the coordinates of the diameter.

Using this we can find the centre of the circle.

<u>Find the centre of the circle.</u>

Centre of the circle is the mid- point of (6, 0) and ( 6, -6)

      Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})

                 =(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)

<u>Find the radius of the circle.</u>

Radius = \frac{Diameter }{2}

Diameter is the distance between the points (6 , 0) and ( 6, - 6)

Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}

               =\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6

Therefore,

    Radius ,r = \frac{6}{2} = 3

<u>Standard equation of a circle:</u>

<u></u>(x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.<u></u>

Therefore , equation of the circle ;

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6 0
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