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ss7ja [257]
3 years ago
14

Divide the following fractions and reduce to lowest terms 2/3 divided by 4/5

Mathematics
1 answer:
pshichka [43]3 years ago
5 0
Well to divide 2 fraction you first have to find a least common number between the 2 bottom numbers in the fractions, we know automaticall that 15 fits in both the 3 and the 5. now u have to find out what to multiply by each number to get 15, for example what number do you multiply by 3 to get 15?? well it will be 5, so go ahead and multiply it by the fraction (note that what you do  in the bottom you have to do in the top) this will give you 10/15, because I multiplied the top and bottom number by 5... lets try the other one what number do you multiply by 5 to get 15?? well it will be 3 so go ahead and multiply that to get 12/15.. now add the top numbers (note that the bottoms always stay the same, you never add or subtract them) when you do you will get 22/15, now you have to see if you can simplify it any further in this case you can't so your final answer is 22/15

Hope this helps
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Wally purchased a bag of marbles on Monday. On Tuesday he gave half of the marbles to his brother, James. On Wednesday he gave t
DiKsa [7]

Answer:

80 marbles

Step-by-step explanation:

so he 50

50+20+10+50=80

so its 80 marbles

6 0
3 years ago
Write the equation
andrew11 [14]

Two things must be performed to make an equation that satisfies this. First, we need to come up with a general equation that is perpendicular to the one in the problem. To do this, the reciprocal of the slope is calculated (negative inverse). The line that is perpendicular to y=1/8x + 2 has a slope of -8. This is what our equation looks like so far:

y’=-8x

This is good, but it doesn’t pass through (1,5). To make it do this, put the point in the equation and solve it - a point on a graph that intersects the line is a “solution” of the equation, so we need to solve for it!

y’ = -8x

(5) = -8(1)

Nope, 5 doesn’t equal -8. Let’s make the two sides equal by adding 13 to the right side.

y’ = -8x + 13

(5) = -8(1) + 13

5=5 - yes!

Our equation that is perpendicular to the one in the question and also passes through the point (1, 5) is y’=-8x + 13.

Hope this helps!

8 0
3 years ago
Trevor is dilating a figure on the coordinate plane by a scale factor of 9/5
ivanzaharov [21]

The original figure will be enlarged by the dilation.

The image and the pre-image will be similar figures.

The corresponding angles of the figures will be congruent.

<h3>What is dilation?</h3>

Dilation is the increase or decrease in the size of a figure by a scale factor k. Dilation produces similar shapes.

If k > 1, this is an enlargement, if k < 1, it is a reduction.

Trevor is dilating a figure on the coordinate plane by a scale factor of 9/5 (>1). Hence:

The original figure will be enlarged by the dilation.

The image and the pre-image will be similar figures.

The corresponding angles of the figures will be congruent.

Find out more on dilation at: brainly.com/question/10253650

5 0
2 years ago
Prove that sec(-pi/4) = sqrt2.
Alika [10]
Sec ( -π/4 ) =
 =1 / cos( -π/4 ) =
= 1 / cos (π/4 ) =
= 1  / √2/2 = 2/√2 = √2
( correct )
3 0
3 years ago
The formula c=<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Ba%5E%7B2%7D%2Bb%5E%7B2%7D%20%20%7D%20" id="TexFormula1" title=" \sq
Amiraneli [1.4K]

Answer:

The required equation is b=\sqrt{c^2-a^2}

Step-by-step explanation:

Consider the provided equation.  

c= \sqrt{a^{2}+b^{2}}

Solve the equation for b.

Square both the sides.

c^2= a^{2}+b^{2}

Subtract a² from both the sides.

c^2-a^2= b^{2}

Square root both the sides.

b=\sqrt{c^2-a^2}

Hence the required equation is b=\sqrt{c^2-a^2}

6 0
3 years ago
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