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Semenov [28]
3 years ago
15

-2|x|=20 Solve for x

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
7 0
Answer: x=5, -5

Explanation:
-2|x| =20
|x| = 10
x=5 x=-5
Dmitriy789 [7]3 years ago
6 0

Answer:

that is an unknown equation

Step-by-step explanation:

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The marketing club at school is opening a student store. They randomly survey 50 students about how much money
yKpoI14uk [10]

Answer:

6.75

Step-by-step explanation:

2+10+1+8+12+6+23+5+8+4+4+3+2.59+5.11+5.18+9.07 = 107.95

now we count how much numbers you added up which equals 16 and divide it with 107.95

107.95/16 = 6.746875

now you cant pay half a penny or such and such

so your round it off at 6.746 to 6.75

and there you have it

8 0
3 years ago
How do i solve it and round to the nearest tenth of a percent
Zepler [3.9K]
Divide 42 by 89
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6 0
4 years ago
Howard's pawn shop bought an antique clock at the wholesale price of $725. Howard marked up the price of the clock
kkurt [141]

Answer:

942.50

Step-by-step explanation:

725×30% or 0.3 = 217.5

217.5+725=942.5

5 0
3 years ago
Round 9296 to the nearest hundred?
Fittoniya [83]
The answer is 9300

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8 0
3 years ago
Read 2 more answers
Cancel the common factor of the numerator and the denominator and write specified expression
lisabon 2012 [21]

Step-by-step explanation:

<em>Hello</em><em>,</em>

<em>I</em><em> </em><em>hope</em><em> </em><em>you</em><em> </em><em>mean</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>that</em><em> </em><em>exists</em><em> </em><em>in</em><em> </em><em>numerator</em><em> </em><em>and</em><em> </em><em>denominator</em><em>,</em><em>right</em><em>.</em>

<em>so</em><em>,</em><em> </em><em>Let's</em><em> </em><em>look</em><em> </em><em>for</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em>, </em>

<em>here</em><em>,</em><em> </em><em>the</em><em> </em><em>expression</em><em> </em><em>is</em><em>, </em>

<em>=</em><em>4</em><em>(</em><em>x-2</em><em>)</em><em>/</em><em> </em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em><em>(</em><em>x-2</em><em>)</em>

<em>so</em><em>,</em><em> </em><em>here</em><em> </em><em>we</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>is</em><em> </em><em>(</em><em>x-2</em><em>)</em>

<em>now</em><em>,</em><em> </em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>it</em><em>.</em><em> </em><em>And</em><em> </em><em>after</em><em> </em><em>cancelling</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em>=</em><em>4</em><em>/</em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em>

<em>Note</em><em>:</em><em>{</em><em> </em><em>we</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>if</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factors</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>multiply</em><em> </em><em>form</em><em>.</em><em>}</em>

<em><u>Hope it helps</u></em><em><u> </u></em>

3 0
3 years ago
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