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Oksana_A [137]
3 years ago
14

Cancel the common factor of the numerator and the denominator and write specified expression

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
3 0

Step-by-step explanation:

<em>Hello</em><em>,</em>

<em>I</em><em> </em><em>hope</em><em> </em><em>you</em><em> </em><em>mean</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>that</em><em> </em><em>exists</em><em> </em><em>in</em><em> </em><em>numerator</em><em> </em><em>and</em><em> </em><em>denominator</em><em>,</em><em>right</em><em>.</em>

<em>so</em><em>,</em><em> </em><em>Let's</em><em> </em><em>look</em><em> </em><em>for</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em>, </em>

<em>here</em><em>,</em><em> </em><em>the</em><em> </em><em>expression</em><em> </em><em>is</em><em>, </em>

<em>=</em><em>4</em><em>(</em><em>x-2</em><em>)</em><em>/</em><em> </em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em><em>(</em><em>x-2</em><em>)</em>

<em>so</em><em>,</em><em> </em><em>here</em><em> </em><em>we</em><em> </em><em>find</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>is</em><em> </em><em>(</em><em>x-2</em><em>)</em>

<em>now</em><em>,</em><em> </em><em>we</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>cancel</em><em> </em><em>it</em><em>.</em><em> </em><em>And</em><em> </em><em>after</em><em> </em><em>cancelling</em><em> </em><em>we</em><em> </em><em>get</em><em>,</em>

<em>=</em><em>4</em><em>/</em><em>(</em><em>x</em><em>+</em><em>5</em><em>)</em>

<em>Note</em><em>:</em><em>{</em><em> </em><em>we</em><em> </em><em>cancel</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factor</em><em> </em><em>if</em><em> </em><em>the</em><em> </em><em>common</em><em> </em><em>factors</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>multiply</em><em> </em><em>form</em><em>.</em><em>}</em>

<em><u>Hope it helps</u></em><em><u> </u></em>

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Simplify into one fraction -2/x+3 - 4/x-5
sergiy2304 [10]
Multiply and divide by the product of the denominators.
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olganol [36]

Answer:

f(x) = x^{3} + 4x^{2} -7x^{} -10^{}

Step-by-step explanation:

The zeros of the polynomial function are given us as -5,-1,2

If the zeros of a polynomial function are α,β,ω, the polynomial function can be obtained using the expression below:

f(x) = (x - α)(x - β)(x - ω)

where α = -5, β = -1, and ω = 2

f(x)=(x-(-5) )(x -(-1))(x - 2) = (x+5)(x+1)(x-2)\\\\f(x)=(x+5)(x^{2} -2x + x -2) = (x+5)(x^{2}  -x-2)\\\\f(x)=x(x^{2}  -x-2)+5(x^{2}  -x-2)\\\\f(x)= x^{3} - x^{2} -2x + 5x^{2} - 5x - 10\\\\f(x)= x^{3} + 4x^{2} -7x - 10

<em>NB: To arrive at the answer, expand the brackets and after expansion, collect like terms to obtain the final answer</em>

4 0
3 years ago
Please help if you can, thank you
Mariulka [41]

Answer:

1.11333333

Step-by-step explanation:

I calculated using Symbolab

sorry if its wrong

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Burka [1]

The equation in which b varies directly as the <em>square</em> root of c is b = 50 · √c. (Correct choice: B)

<h3>What is the equation of the direct variation between two variables?</h3>

In this problem we have a case of <em>direct</em> variation between two variables, which is mathematically described by a <em>direct proportionality</em> model, whose form and characteristics are shown below:

b ∝ √c

b = k · √c      (1)

Where k is the <em>proportionality</em> constant.

First, we determine the value of the constant of proportionality by substituting on b and c and clearing the variable: (b = 100, c = 4)

k = b / √c

k = 100 / √4

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Then, the equation in which b varies directly as the <em>square</em> root of c is b = 50 · √c. (Correct choice: B)

To learn more on direct variation: brainly.com/question/14254277

#SPJ1

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