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pshichka [43]
3 years ago
8

What is 3 over 5 + 1 over 9

Mathematics
1 answer:
koban [17]3 years ago
6 0

Answer:

2/5

Step-by-step explanation:

3/5 + 1/9

= 12+6/45

= 18/45 which is 2/5

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Point O is the center of the circle in the diagram. What is m∠BCA ?
netineya [11]
The sum of angle around a point equal 360°
so (BOA) = 360-250=110°
and the sum of angle in the shape CAOB = 360°
so BCA = 360-(110+90+90)= 70°
THE ANSWER IS C.70°
7 0
3 years ago
Molly had 8 apples jim has 8 how many do they have all together
Norma-Jean [14]

Answer:

16

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLEASE SHOW ALL THE STEPS THAT YOU USE TO SOLVE THIS PROBLEM
Mademuasel [1]

Answer:

{x = 1 , y=1, z=0

Step-by-step explanation:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

{-2 x - y + z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x - 3 y - 2 z = -3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+3 y + 2 z = 3 | (equation 2)

{0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y + 6 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+5 y+0 z = 5 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

{0 x+y+0 z = 1 | (equation 2)

{0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer:  {x = 1 , y=1, z=0

6 0
2 years ago
Who knows how to do this ​
IgorC [24]

Answer:

<h2>144 {cm}^{2}</h2>

Step-by-step explanation:

Given,

As we know that the all sides of the square are equal.

Length of a square paper = 12 cm

Area of square = ?

Now, let's find the area of square

=  {l}^{2}

plugging the value of length,

{(12)}^{2}

Evaluate the power

= 144 square cm

Hope this helps...

Best regards!!

7 0
3 years ago
HELP PLEASE
nordsb [41]

Answer:

<h3>perpendicular line:    y = -¹/₆ x + 4¹/₃ </h3><h3>  parallel line:              y = 6x - 45 </h3>

Step-by-step explanation:

y=m₁x+b₁   ⊥   y=m₂x+b₂   ⇔    m₁×m₂ = -1

{Two lines are perpendicular if the product of theirs slopes is equal -1}

y = 6x - 7   ⇒   m₁=6

6×m₂ = -1        ⇒    m₂ = -¹/₆

 

The line y=-¹/₆ x+b passes through point (8, 3) so the equation:

3 = -¹/₆ ×8 + b must be true

3 = -⁴/₃ + b

b = 4¹/₃

Therefore equation in  slope-intercept form:

                                                     y = -¹/₆ x + 4¹/₃

y=m₁x+b₁   ║   y=m₂x+b₂   ⇔    m₁ = m₂

{Two lines are parallel if  their slopes are equal}

y = 6x - 7   ⇒   m₁=6   ⇒   m₂=6

The line y=6x+b passes through point (8, 3) so the equation:

3 = 6×8 + b must be true

3 = 48 + b

b = -45

Therefore equation in  slope-intercept form:

                                                     y = 6x - 45

7 0
3 years ago
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