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Citrus2011 [14]
2 years ago
6

Select three ratios that are equivalent to 8 : 5

Mathematics
2 answers:
Gennadij [26K]2 years ago
7 0

Answer:

16:10

48:30

32:50

Step-by-step explanation:

zimovet [89]2 years ago
6 0
40:25
16:10
24:15
hope this helps!
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8x+8(c+8)-6 show work its for my homework i get it but im just making sure i did it right:)
ioda
8x+8c+164-6
=8x+8c+158
7 0
3 years ago
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Here is Triangle A. Lin created a scaled copy of Triangle A with an area of 72 square units. a. How many times larger is the are
PSYCHO15rus [73]

Answer:

The answer is below

Step-by-step explanation:

a) Triangle A is attached in the image below.

The base of triangle A is 3 units and its height is 3 units. The area of a triangle  is given as:

Area = (1/2) × base × height

Area of triangle A = (1/2) × base × height = (1/2) × 3 × 3 = 4.5 unit²

Area of the scaled copy = 72 unit²

Ratio of area = Area of the scaled copy / Area of triangle A = 72 unit² / 4.5 unit² = 16

Hence the scaled copy area is 16 times larger than that of triangle A.

b) For the scaled copy:

Area of the scaled copy = (1/2) × base × height = 72 unit²

base × height = 144

Since the base and height are equal

base² = 144

base = 12, also height = 12

Base of scaled copy = 12 = 4 × base of triangle A

Therefore the scale factor used is 4

7 0
3 years ago
Binomial Expansion/Pascal's triangle. Please help with all of number 5.
Mandarinka [93]
\begin{matrix}1\\1&1\\1&2&1\\1&3&3&1\\1&4&6&4&1\end{bmatrix}

The rows add up to 1,2,4,8,16, respectively. (Notice they're all powers of 2)

The sum of the numbers in row n is 2^{n-1}.

The last problem can be solved with the binomial theorem, but I'll assume you don't take that for granted. You can prove this claim by induction. When n=1,

(1+x)^1=1+x=\dbinom10+\dbinom11x

so the base case holds. Assume the claim holds for n=k, so that

(1+x)^k=\dbinom k0+\dbinom k1x+\cdots+\dbinom k{k-1}x^{k-1}+\dbinom kkx^k

Use this to show that it holds for n=k+1.

(1+x)^{k+1}=(1+x)(1+x)^k
(1+x)^{k+1}=(1+x)\left(\dbinom k0+\dbinom k1x+\cdots+\dbinom k{k-1}x^{k-1}+\dbinom kkx^k\right)
(1+x)^{k+1}=1+\left(\dbinom k0+\dbinom k1\right)x+\left(\dbinom k1+\dbinom k2\right)x^2+\cdots+\left(\dbinom k{k-2}+\dbinom k{k-1}\right)x^{k-1}+\left(\dbinom k{k-1}+\dbinom kk\right)x^k+x^{k+1}

Notice that

\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!}{\ell!(k-\ell)!}+\dfrac{k!}{(\ell+1)!(k-\ell-1)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(\ell+1)}{(\ell+1)!(k-\ell)!}+\dfrac{k!(k-\ell)}{(\ell+1)!(k-\ell)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(\ell+1)+k!(k-\ell)}{(\ell+1)!(k-\ell)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(k+1)}{(\ell+1)!(k-\ell)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{(k+1)!}{(\ell+1)!((k+1)-(\ell+1))!}
\dbinom k\ell+\dbinom k{\ell+1}=\dbinom{k+1}{\ell+1}

So you can write the expansion for n=k+1 as

(1+x)^{k+1}=1+\dbinom{k+1}1x+\dbinom{k+1}2x^2+\cdots+\dbinom{k+1}{k-1}x^{k-1}+\dbinom{k+1}kx^k+x^{k+1}

and since \dbinom{k+1}0=\dbinom{k+1}{k+1}=1, you have

(1+x)^{k+1}=\dbinom{k+1}0+\dbinom{k+1}1x+\cdots+\dbinom{k+1}kx^k+\dbinom{k+1}{k+1}x^{k+1}

and so the claim holds for n=k+1, thus proving the claim overall that

(1+x)^n=\dbinom n0+\dbinom n1x+\cdots+\dbinom n{n-1}x^{n-1}+\dbinom nnx^n

Setting x=1 gives

(1+1)^n=\dbinom n0+\dbinom n1+\cdots+\dbinom n{n-1}+\dbinom nn=2^n

which agrees with the result obtained for part (c).
4 0
3 years ago
What is an equation in slope-intercept form of the line that passes through the points (−2, −2) and (1, 7)? A.y = 4x + 3 B.y − 7
antoniya [11.8K]

Answer:

C.y = 3x + 4

Step-by-step explanation:

We have two points, so we can find the slope

m = (y2-y1)/ (x2-x1)

   = (7--2)/ (1--2)

   = (7+2)/(1+2)

    = 9/3

    =3

The slope is 3

We can find the point slope form of the line

y-y1 = m(x-x1)

y-7 = 3(x-1)

Distribute

y-7 =3x-3

Add 7 to each side

y-7+7 = 3x-3+7

y = 3x+4

This is in slope intercept form (y=mx+b)

8 0
3 years ago
-4(50x-20)=10x+15+23
dlinn [17]

Answer:

0.2 or 1/5

Step-by-step explanation:

-4(50x - 20) = 10x + 15 + 23

-200x + 80 = 10x + 38

80 = 210x + 38

42 = 210x

0.2 = x

Hope this helps! Pls give brainliest!

3 0
2 years ago
Read 2 more answers
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