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sammy [17]
3 years ago
11

How do you find the sum of the first 20 terms of sequence

Mathematics
1 answer:
andriy [413]3 years ago
8 0

The formula to find the sum of the first n terms of our sequence is n divided by 2 times the sum of twice the beginning term, a, and the product of d, the common difference, and n minus 1. The n stands for the number of terms we are adding together.
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I need with 2n-7=5n-10 also
melomori [17]
2n - 7 = 5n -10
-5n    -5n
-3n - 7= -10
       +7   +7
-3n = -3 
-3/-3    -3/-3
    n= 1
6 0
3 years ago
Can someone please help ? :(
Anika [276]

Answer:

I'll list the answers as coordinates (just input the second number in each coordinate)

(-2, 11)

(0, 1)

(2, -9)

(4, -19)

Step-by-step explanation:

So you see how the x column is filled out? You plug in the numbers in each area and solve for y.

So we start off with -2. You take the x out and place -2 instead. Your equation should look like this:

y = -5 (-2) + 1

Next you multiply -5 and -2, giving you 10. Your equation would look like this now:

y = 10 + 1

Next you add 10 and 1 together, and you have your answer. Keep doing the same thing, but instead of -2 for x, use 0, 2, and 4.

Hope I helped! Have a nice day or night! ^-^

8 0
3 years ago
Read 2 more answers
50 POINTS!
padilas [110]
To double the principle the formula is
2p=p e^rt
2=e^rt
2=e^0.12t
Solve for t
T=(log(2)÷log(e))÷0.12
T=5.78 years
5 0
3 years ago
Rory rode his bike a total of 7.75 miles last week. He biked the same distance each of the 5 days he rode. How many miles did Ro
exis [7]

Answer:

Rory rode 1.55 miles each day

Step-by-step explanation:

7.75 divided by 5

6 0
2 years ago
If log(base4)x=2.5 and log(base Y)125=-3/2, find the numerical value of x/y, in simplest form.
Naya [18.7K]
X = (2^2)^(2.5) 
<span>x = 2^(2 * 2.5) </span>
<span>x = 2^5 </span>
<span>x = 32 
</span>y^(-3/2) = 125 
<span>y^(-3) = 125^2 </span>
<span>y^(-3) = (5^3)^2 </span>
<span>y^(-3) = (5^2)^3 </span>
<span>y^(-3) = 25^3 </span>
<span>y = 25^(-1) </span>
<span>y = 1/25 </span>


<span>x/y => </span>
<span>32 / (1/25) => </span>
<span>32 * 25 => </span>
<span>800 is the simplest form of above
</span>
5 0
3 years ago
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