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2 years ago

12

If xy=0 what must be true about either x or y?

1 answer:

Anettt [7]2 years ago

6 0

Answer:

D. either x or y must equal 0

Step-by-step explanation:

Its given that xy = 0

Remember that product of two numbers can be zero only if:

Both of them are zero or Either of them is zero as zero multiplied to any non-zero number will always be equal to zero. This is known as Zero Product Property.

So, if the product of x and y is equal to 0 there are two possibilities:

Both x and y are equal to 0
Either x or y must be equal to 0

Note that the condition both x and y are equal to zero is not a must condition, because even if one of them is equal to zero, the entire expression will be equal to zero.

Hence, the condition which has to be true in all cases for xy = 0 is:

D. either x or y must equal 0

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675/8 as a mixed number in simplest form.

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2 years ago

ludmilkaskok [199]

Answer:

2/5

Step-by-step explanation:

There's 5 jellybeans in the bag total and of the five, 2 of them are red, so the probability that Cynthia gives him 2 reds is 2/5.

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2 years ago

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Which function is even? Check all that apply.

iris [78.8K]

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2 years ago

Consider F and C below. F(x, y, z) = yz i + xz j + (xy + 6z) k C is the line segment from (2, 0, −2) to (5, 4, 2) (a) Find a fun

WITCHER [35]

Answer:

Required solution (a) $f(x,y,z)=xyz+3z^2+C$ (b) 40.

Step-by-step explanation:

Given,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k$

(a) Let,

$F(x,y,z)=yz \uvec i +xz\uvec j+(xy+6z)\uvex k=f_x \uvec{i} +f_y \uvex{j}+f_z\uvec{k}$

Then,

$f_x=yz,f_y=xz,f_z=xy+6z$

Integrating $f_x$ we get,

$f(x,y,z)=xyz+g(y,z)$

Differentiate this with respect to y we get,

$f_y=xz+g'(y,z)$

compairinfg with $f_y=xz$ of the given function we get,

$g'(y,z)=0\implies g(y,z)=0+h(z)\implies g(y,z)=h(z)$

Then,

$f(x,y,z)=xyz+h(z)$

Again differentiate with respect to z we get,

$f_z=xy+h'(z)=xy+6z$

on compairing we get,

$h'(z)=6z\implies h(z)=3z^2+C$ (By integrating h'(z)) where C is integration constant. Hence,

$f(x,y,z)=xyz+3z^2+C$

(b) Next, to find the itegration,

$\int_C \vec{F}.dr=\int_C \nabla f. d\vec{r}=f(5,4,2)-f(2,0,-2)=(52+C)-(12+C)=40$

3 0

3 years ago

Freyda has a circular rug with a radius of 120 centimeters. The fringe on the outside edge of the rug needs to be replaced. What

Gnom [1K]

Answer:

The Fringe of the rug is 754 cm.

Step-by-step explanation:

Given:

radius = 120 cm

We need to find the fringe of the outside rug.

Solution:

Since the rug is in the circular form.

We can say that fringe of the outside edge of the rug can be equal to circumference of the circle.

Then we will find the Circumference of the circle.

Circumference of the circle is given 2 times 'π' times radius 'r'.

framing in equation form we get;

Circumference of the circle = $2\pi r$

Circumference of the circle = $2 \times \pi \times 120 = 753.98 \approx 754\ cm$

Hence the Fringe of the rug is 754 cm.

8 0

2 years ago