All categories

3 years ago

What’s the value of x in this equation???? Thank u!

Mathematics

2 answers:

andre [41]3 years ago

7 0

Answer:

x = 9

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

50° is an exterior angle of the triangle, thus

38 + 4x - 24 = 50 , that is

14 + 4x = 50 ( subtract 14 from both sides )

4x = 36 ( divide both sides by 4 )

x = 9

k0ka [10]3 years ago

3 0

Answer:

$\huge\boxed{\sf x = 9}$

Step-by-step explanation:

The measure of the exterior angle is equal to the sum of non-adjacent interior angles.

So,

50 = 38 + 4x - 24

50 = 4x + 14

Subtract 14 to both sides

50 - 14 = 4x

36 = 4x

Divide 4 to both sides

36 / 4 = x

x = 9

$\rule[225]{225}{2}$

Hope this helped!

You might be interested in

the graph shows the first five terms in a geometric sequence what is the iterative rule for the sequence

algol [13]

The iterative rule for the sequence is a_n = 8 · ( 0.5 )ⁿ ⁻ ¹

<h3>Further explanation</h3>

Firstly , let us learn about types of sequence in mathematics.

Arithmetic Progression is a sequence of numbers in which each of adjacent numbers have a constant difference.

$\boxed{T_n = a + (n-1)d}$

$\boxed{S_n = \frac{1}{2}n ( 2a + (n-1)d )}$

<em>Tn = n-th term of the sequence</em>

<em>Sn = sum of the first n numbers of the sequence</em>

<em>a = the initial term of the sequence</em>

<em>d = common difference between adjacent numbers</em>

Geometric Progression is a sequence of numbers in which each of adjacent numbers have a constant ration.

$\boxed{T_n = a ~ r^{n-1}}$

$\boxed{S_n = \frac{a( 1 - r^n ) }{1 - r}}$

<em>Tn = n-th term of the sequence</em>

<em>Sn = sum of the first n numbers of the sequence</em>

<em>a = the initial term of the sequence</em>

<em>r = common ratio between adjacent numbers</em>

Let us now tackle the problem!

<u>Given:</u>

a₁ = 8

a₂ = 4

a₃ = 2

a₄ = 1

<u>Solution:</u>

<em>Firstly , we find the ratio by following formula:</em>

$r = a_2 \div a_1 = 4 \div 8 = 0.5$

$\texttt{ }$

<em>The iterative rule for the sequence:</em>

$a_n = a_1 \cdot~ r^{n-1}$

$a_n = 8 \cdot~ (0.5)^{n-1}$

$\texttt{ }$

<h3>Learn more</h3>

Geometric Series : brainly.com/question/4520950
Arithmetic Progression : brainly.com/question/2966265
Geometric Sequence : brainly.com/question/2166405

<h3>Answer details</h3>

Grade: Middle School

Subject: Mathematics

Chapter: Arithmetic and Geometric Series

Keywords: Arithmetic , Geometric , Series , Sequence , Difference , Term

6 0

3 years ago

Brainlist at the first one to answer!!!!!! Plz........ASAP!!!

Makovka662 [10]

Answer: ellipse

Step-by-step explanation:

3 0

3 years ago

How do I determine the range.

Nikitich [7]

Answer:

y: (5, -5)

Step-by-step explanation:

5 0

3 years ago

Simplify each exponential expression using the properties of exponents and match it to the correct answer.

saveliy_v [14]

1) (2 $\times$ 3^-2)^3 (5 $\times$ 3^2)^2 / (3^-2)(5 $\times$ 2)^2 = 2

2) (3^3) (4^0)^2 (3 $\times$ 2)^-3 (2^2) = 1/2

3) (3^7 $\times$ 4^7) (2 $\times$ 5)^-3 (5)^2 / (12^7) (5^-1) (2^-4) = 2

4) (2.3)^-1 (2^0) / (2.3)^-1 = 1

<u>Step-by-step explanation</u>:

Step 1 :

(2 $\times$ 3^-2)^3 (5 $\times$ 3^2)^2 / (3^-2)(5 $\times$ 2)^2

⇒ (2^3) (3^-6) (5^2) (3^4) / (3^-2) (10^2)

⇒ (2.2^2.5^2) (3^-6.3^4) / (3^-2) (10^2)

⇒ (2)(10^2) (3^-2) / (3^-2) (10^2)

⇒ 2

Step 2 :

(3^3) (4^0)^2 (3 $\times$ 2)^-3 (2^2)

Any number with power 'zero' is 1.

⇒ (3^3) (1^2) (3^-3) (2^-3) (2^2)

⇒ (2^(-3+2))

⇒ 2^-1 = 1/2

Step 3 :

(3^7 $\times$ 4^7) (2 $\times$ 5)^-3 (5)^2 / (12^7) (5^-1) (2^-4)

⇒ (12^7) (2^-3) (5^-3) (5^2) / (12^7) (5^-1) (2^-4)

⇒ (2^-3) (5^(-3+2)) / (5^-1) (2^-4)

⇒ (2^-3) (5^-1) / (5^-1) (2^-4)

⇒ 1 / (2^-1)

⇒ 2

Step 4 :

(2.3)^-1 (2^0) / (2.3)^-1

⇒ (2^0)

⇒ Any number with power 'zero' is 1

⇒ 1

8 0

3 years ago

Simplify: <br><br> a)23p-7p<br> b)3ab-9ab+7ab

natima [27]

a) 16p

b) 1ab

hope i helped

5 0

3 years ago