L=1.5w
P=l+w
40=2.5 w
W=16
L=1.5(16) =24
Length is 24
Width is 16
<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution
Given the above information;
AC=AB, therefore ABC is an isosceles triangle.
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60
Answer:
-460
Step-by-step explanation:
I multiply by splitting the numbers into digits. So for the 90, in my head I did 5 × 90, which is 450. Then I did 2 × 5, this is 10. Now I added those up to make 460. Considering the 92 is negative, the answer will also be negative.