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Snezhnost [94]
4 years ago
5

Rewrite the following radical expression in rational exponent form

Mathematics
2 answers:
creativ13 [48]4 years ago
6 0
The roots can be written as exponents:
\sqrt[x]{ {a}^{y} }  =  {a}^{ \frac{y}{x} }  \\  \\  { \sqrt[x]{a} }^{y}   =  {a}^{ \frac{y}{x} }
In this problem, we know that the root is a square root because there is no number on the left side of the root.

So we could write that as:
{x}^{ \frac{5}{2} }
Kitty [74]4 years ago
3 0

(\sqrt{x})^{5}


Rewrite √ as the power of 1/2

⇒ (x^{\frac{1}{2}})^{5}

⇒x^{\frac{5}{2}}


\text {Answer: } x^{\frac{5}{2}}


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a rectangular laboratory has a length equal to one and a half times its width and a perimeter of 40m. find its length and width
tresset_1 [31]
L=1.5w
P=l+w
40=2.5 w
W=16
L=1.5(16) =24

Length is 24
Width is 16
8 0
2 years ago
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This is one fourth of the course, so 25%.
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3 years ago
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Fie O centrul unui cerc si doua unghiuri la centru adiacente AOB si BOC.Stiind ca masura unghiului AOB = 120 si masura BOC= 150,
kodGreya [7K]

<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution

Given the above information;
AC=AB, therefore ABC is an isosceles triangle. 
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60


4 0
3 years ago
5 × -92 = <br> Just a quick response on how to solve this, thanks a ton!
Colt1911 [192]

Answer:

-460

Step-by-step explanation:

I multiply by splitting the numbers into digits. So for the 90, in my head I did 5 × 90, which is 450. Then I did 2 × 5, this is 10. Now I added those up to make 460. Considering the 92 is negative, the answer will also be negative.

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