Remember that
If the given coordinates of the vertices and foci have the form (0,10) and (0,14)
then
the transverse axis is the y-axis
so
the equation is of the form
(y-k)^2/a^2-(x-h)^2/b^2=1
In this problem
center (h,k) is equal to (0,4)
(0,a-k)) is equal to (0,10)
a=10-4=6
(0,c-k) is equal to (0,14)
c=14-4=10
Find out the value of b
b^2=c^2-a^2
b^2=10^2-6^2
b^2=64
therefore
the equation is equal to
<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>
The events are independent...because after the first pick, the card was replaced...that means the second pick has the same sample space. In other words, the first pick is not gonna affect the 2nd pick
8 football, 2 basketball...total of 10
P(1st pick is football) = 8/10 which reduces to 4/5
replace
P(2nd pick is basketball) = 2/10 which reduces to 1/5
P (both) = 4/5 * 1/5 = 4/25 = 0.16 <==
Answer:
Do you mean y? if you did it should be 1/6 or 1.666666 repeating.
Step-by-step explanation:
I needed the 6y to = 1 so I did the inverse of it by and got 1 so y should = 1/6
They are not congruent. Hope this helped!
The answer is 27 loaves. please do not open the link on the other answer! it’s a scam
