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sleet_krkn [62]
3 years ago
5

Which of the following lists of ordered pairs is a function ?

Mathematics
2 answers:
lianna [129]3 years ago
5 0
B. Because it doesn’t repeat in either x or y
Nitella [24]3 years ago
3 0

To be a function, for any X value( input) you can only have one Y(output value).

In A) there are two x values of 2, but each one has a different Y value, so this cannot be a function.

In C, there are two x values of 1, each with a different Y value, so also cannot be a function.

D) has two X values of 0, and each has a different Y value so cannot be a function.

The correct answer would be B.

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Mikaela’s friends brought a big box of crackers to the movie theater. 53 crackers are
slamgirl [31]

Answer:

123 crackers

Step-by-step explanation:

If 1/3 of the box contains sesame seed crackers, then, 2/3 of the box contains whole wheat and cheese flavored crackers.

Total number of whole wheat and cheese flavored crackers = 53 + 29 = 82

Let x be the total number of crackers in the box, so we will have the equation

2/3 x= 82

x = 82 ÷ 2/3; we will get

X =82 x 3/2

X = 123 crackers

4 0
3 years ago
A scale drawing of a park is 1 inch equal to 15 feet. What is the actual area of the park?
sesenic [268]

Answer:

Step-by-step explanation:

To get the current area of the park you must multiply by 15 the number of inches indicated on the map.

4 0
3 years ago
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Lina20 [59]
Interest earned in the amount of $2.75
4 0
4 years ago
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What is the equation of the line that has a y intercept of (0,-3) and passes the point (-9,-9)
zavuch27 [327]

Answer:

y = 2/3x - 3

Step-by-step explanation:

First calculate the slope: y2 - y1 divided by x2 - x1

Slope: -6/-9 = 2/3

The y-intercept is -3

The equation of a line: y = mx + b

y = 2/3x - 3

4 0
3 years ago
Find the equation of the line that passes through point A (1,7) and B (-3, -1)
amid [387]

Answer:

The equation of the line is 2 x - y + 5 = 0.

Step-by-step explanation:

Here the given points are A( 1, 7) & B( -3, - 1) -

Equation of a line whose points are given such that

( x_{1}, y_{1} ) & ( x_{2}, y_{2} )-

 y - y_{1}  = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }   ( x - x_{1}  )

i.e. <em> y - 7= \frac{- 1 - 7}{ -3-1}  ( x- 1)</em>

<em>       y - 7 =  \frac{- 8}{- 4} ( x -1)</em>

<em>       y - 7 =  2 ( x - 1) </em>

<em>       y - 7  =   2  x - 2</em>

<em>       2 x - y + 5 = 0</em>

Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1)  is 2 x - y  + 5 = 0.

6 0
3 years ago
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