Answer:
Step-by-step explanation:
The circumcenter is equidistant from the three vertices of the triangle. From the figure shown, we will prove DA = DB = DC. 2) DA = DB, DC = DB(If a point is on the perp. bisector of a segment, it is equidistant from each endpoint of the segment.)
Answer:
a. The percentage of vehicles who pass through this construction zone who are exceeding the posted speed limit =90.82%
b. Percentage of vehicles travel through this construction zone with speeds between 50 mph and 55 mph= 2.28%
Step-by-step explanation:
We have to find
a) P(X>40)= 1- P(x=40)
Using the z statistic
Here
x= 40 mph
u= 44mph
σ= 3 mph
z=(40-44)/3=-1.33
From the z-table -1.67 = 0.9082
a) P(X>40)=
Probability exceeding the speed limit = 0.9082 = 90.82%
b) P(50<X<55)
Now
z1 = (50-44)/3 = 2
z2 = (55-44)/3= 3.67
Area for z>3.59 is almost equal to 1
From the z- table we get
P(55 < X < 60) = P((50-44)/3 < z < (55-44)/3)
= P(2 < z < 3.67)
= P(z<3.67) - P(z<2)
= 1 - 0.9772
= 0.0228
or 2.28%
Answer:
12
(If needed explanation ask in the comments! ty)
Hope This Helps! •v•
Answer:
(88a+80)(8a+8)
88a(8a+8)+80(8a+8)
704a²+704a+640a+640
704a²+1344a+640
(40y+zy)(4y+zy)
40y(4y+zy)+zy(4y+zy)
160y²+40zy²+4zy²+z²y²
160y²+44zy²+z²y²
Step-by-step explanation:
i hope this will help you
Answer:
Option (1)
Step-by-step explanation:
From the picture attached,
Triangle CAB is a right triangle.
Therefore, m∠1 = 90°
Similarly, m∠ACD = 90°
m∠ACD = m∠ACB + m∠BCD = 90°
= m∠3 + m∠4 = 90°
Since m∠4 = 35°,
m∠3 + 35° = 90°
m∠3 = 90° - 35°
= 55°
In the triangle ABC,
m∠ACB + m∠CBA + m∠BAC = 180° [Property of a triangle]
m∠3 + m∠2 + m∠1 = 180°
55° + m∠2 + 90° = 180°
m∠2 + 145° = 180°
m∠2 = 180° - 145°
= 35°
Since, AB║CD and BC is a transverse,
Therefore, m∠2 = m∠4 = 35° [Alternate interior angles]
Option (1) is the correct option.
