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viva [34]
3 years ago
5

Alicia is writing the program for a video game. For one part of the game she uses the rule to move points on the screen.

Mathematics
1 answer:
lianna [129]3 years ago
8 0
I'm doing the same test... though my inputs are (-6,0) and (3, -4)
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Hey, your answer is C = 12
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How do you solve 13y^2-5yx-8x^2
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<span>Step  1  :</span><span>Simplify 13y2-5yx - 23x2</span><span> 
1.1 </span>   Factoring   <span> 13y2 - 5yx - 8x2</span> Try to factor this multi-variable trinomial using trial and error<span>  </span>Found a factorization  :  (y - x)•(13y + 8x)
Final result :<span> (y - x) • (13y + 8x)</span>
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3 years ago
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the width of a rectangle is 7 feet less than it's length.if the area of the rectangle is 170 square feet, then find the length a
balu736 [363]

let length = x

width is 7 feet less than length

width = x-7

area = length *width

area = x(x-7)

170=x²-7x

x²-7x-170=0

x²-17x+10x-170=0

x(x-17)+10(x-17)=0

(x-17)(x+10)=0

x=17 or x=-10

since length cannot be negative so x=17

and width =x-7 =17-7=10

length =17 feet and width =10 feet

7 0
3 years ago
Which of the following equations has only one solution? x2 + 4x + 4 = 0 x2 + x = 0 x2 - 1 = 0
Nady [450]
<span>you can solve all quadratic equations using this method:
---
x^2 + 4x + 4 = 0
---
the above quadratic equation is in standard form, with a=1, b=4, and c=4
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1 4 4
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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this quadratic has ONE real root (the x-intercept), which is:
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x^2 + x = 0
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the above quadratic equation is in standard form, with a=1, b=1, and c=0</span>
4 0
3 years ago
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The function f(r) = π determines the area of a circle in cm2, A, in terms of the radius of the circle in cm, r. a. Write a funct
ollegr [7]

Answer with Step-by-step explanation:

We are given that

a.f(r)=\pi r^2

A=\pi r^2

r^2=\frac{A}{\pi}

g(A)=r=\sqrt{\frac{A}{\pi}}

b.Radius=2.58 cm

Substitute the values in the formula and \pi=3.14

f(2.58)=3.14(2.58)^2=20.9 cm^2

Hence, the area of circle =20.9 square cm

c.Area of circle=1530 square cm

r=\sqrt{\frac{1530}{3.14}}=22.07 cm

Hence, the radius of circle=22.07 cm

c.Area of circle of radius 15.2 cm=A_1=3.14(15.2)^2=725.47 cm^2

Area of circle of radius 15.1 cm=A_2=3.14(15.1)^2=715.95 cm^2

A_1-A_2=725.47-715.95=9.52 cm^2

Hence, the area of circle whose radius is 15.2 cm is greater than the area of circle of radius 15.1 cm by 9.52 square cm .

6 0
3 years ago
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