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3 years ago

I need help please :/

Mathematics

1 answer:

OleMash [197]3 years ago

7 0

Part (a)

Plug in y = 0 and solve for x. Use the zero product property

y = x(x+3)(x-2)

0 = x(x+3)(x-2)

x(x+3)(x-2) = 0

x = 0 or x+3 = 0 or x-2 = 0 .... zero product property

x = 0 or x = -3 or x = 2

The three roots or zeros are x = 0 or x = -3 or x = 2

================================================

Part (b)

The roots of the graph are: x = -2, x = 1, x = 3. Each root is where the graph crosses or touches the horizontal x axis.

Note how x = 0 is found in part (a), but not found here. This is one example where the graphs don't match. Another would be x = -3 is in part (a), but not here.

So that's why the graph does <u>not</u> match with the function in part (a)

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The library is 1.75 miles directly north from the school. The park is 0.6 miles directly south of the school. How far away is th

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Answer:

2.35 miles

Step-by-step explanation:

Please find the attachment for visual understanding.

We are told that the library is 1.75 miles directly north from the school and the park is 0.6 miles directly south of the school.

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3 years ago

I need help with this equation 20 points help quick

Mademuasel [1]

Answer:

The equation of the graph after translating one unit to the left is;

$y = \left | \dfrac{x}{2} - \dfrac{3}{2} \right |+3$

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The given equation is $y = \left | \dfrac{1}{2}\cdot x - 2 \right |+3$

We note that minimum value of y = 3, where 1/2·x - 2 = 0 and x = 4

Therefore, in moving one unit to the left, we have at the y-intercept where slope of the graph has become inverted (reflection of the real graph) we add one to the x value as follows;

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3 years ago

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UNO [17]

Answer:

Step-by-step explanation: was the same same

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3 years ago

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Serjik [45]

Answer:

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2 years ago

Please help me ASAP it’s times THANK U

goblinko [34]

Answer:

Only choices C and D are solutions

Step-by-step explanation:

6x + 3y = -15

y = -2x - 5

6x + 3y = -15

6x + 3(-2x - 5) = -15

6x - 6x - 15 = -15

0 = 0

Since 0 = 0 is a true statement, both equations of this system are the same equation and represent a single line on the coordinate plane.

We need to check each choice in just one equation.

Let's use the second equation.

y = -2x - 5

(2, 7)

7 = -2(2) - 5

7 = -4 - 5

7 = -9 False

Not a solution

(5, 0)

0 = -2(5) - 5

0 = -10 - 5

0 = -15 False

Not a solution

(-3, 1)

1 = -2(-3) - 5

1 = 6 - 5

1 = 1 True

Solution

-13 = -2(4) - 5

-13 = -8 - 5

-13 = -13 True

Solution

Answer: Only choices C and D are solutions

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3 years ago