$y - y_1 = m(x - x_1) \\ \\ y - 0 = \bigg[ \frac{2b}{(2a - c)} \bigg] (x - c) \\ \\ y = \bigg[ \frac{2b}{(2a - c)} \bigg]x - \bigg[ \frac{2b}{(2a - c)} \bigg]c \\ \\ \purple { \boxed{ \bold{y = \bigg[ \frac{2b}{(2a - c)} \bigg]x - \bigg[ \frac{2bc}{(2a - c)} \bigg]}}} \\$

6 0

3 years ago

Solve for v in terms of s, t, v. u=-tsv

mrs_skeptik [129]

Suppose an object starts moving at u and gains an acceleration of a. After time t, it gets a speed v after travelling a distance of s.

a = (v - u) / t => v - u = at

v = u + at

s = ut + 1/2(v - u) t

s = ut + 1/2 (at) t

s = ut + 1/2 at2

v2 = (u + at)2

v2 =u2 + 2uat + a2t2

v2 = u2 + 2a (ut + 1/2 at2)

v2 = u2 + 2as

6 0

2 years ago

In a jar, the numbers of white, black and red marbles are in ratio of 5:11:8. If the total number of marbles is 144, then how ma

Dominik [7]

48 red marbles

Let me know if you want an explanation and I’ll be happy to explain

7 0

3 years ago