Company A: 120 + 0.50x
Company B: 60 + 0.60x
Company A = Company B (solve for x)
(Here, x = miles)
120 + 0.50x = 60 + 0.60x
120 - 60 = 0.60x - 0.50x
60 = 0.10x
600 = x
I believe that the answer is 22x
QUESTION:
The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.
ANSWER:
Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–
- P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.
Since there are 10 digits to choose from, we can assume that n = 10.
Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.
Now, plug these values into the formula and solve:
= 10!(10−5)!
= 10!5!
= 10⋅9⋅8⋅7⋅6
= 30240.
Answer: A
Step-by-step explanation:
If you put 0 in for x, then you would be dividing by 0. Dividing by 0 is always undefined.
Answer:
the least cookies someone can buy from one person is 6
Step-by-step explanation:
