This is an Arithmetic Progression with 1st term 11 and common difference d=6
Number of Rows Number of seats Common difference " d"
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1st a₁ = 11
2nd a₁+d =17 d =2nd - 1st = 6
3rd a₁ +2d = 23 d =3rd - 2nd = 6
4th a₁ +3d = 29 d= 4th - 3rd = 6
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nth ROW a(n) = a₁ + (n-1)d
18th ROW a₁₈ = 11 + (18-1).6 = 11+(17)(6) = 113
General equation to predict the number of seat an the nth row:
Number of seats in nth row = a₁ + (n-1).d
Answer:
We get that √48 = 2⋅2√3. Lastly, step three says to simplify, so we go ahead and multiply the 2⋅2 outside of the square root to get 4√3. That's it! We get that √48 = 4√3.
Step-by-step explanation:
Step-by-step explanation:
Based off of the fitted line, we obtain expected values, given an input. If the input is 0 minutes remaining (meaning a student turns in a test with no time remaining), the expected value of their exam score is 87.
Answer:
562.5 mph
Step-by-step explanation:
First, let's find how fast the car is going in miles per hour. We do this by dividing the miles by how many hours it took:
225/4 = 56.25
The car was going 56.25 mph
A high-speed train is ten times faster than this car so you multiply 56.25 by 10
(10)(56.25) = 562.5
The train's speed is 562.5 mph
<em>Hope this helps!</em>
<em>- Kay :)</em>
